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Contact [7]
3 years ago
5

How many three digit numbers greater than 500 can you form using the digits 2 6 8 exactly once each

Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0
6^8x2  6x2^8 is all i can think of
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What is the radius of a sphere if its surface area is 2,122.64 square inches? (Use 3.14 for π.) 11 in. 13 in. 121 in. 169 in.
crimeas [40]
To solve this, we are going to use the surface are of a sphere formula: A=4 \pi r^2
where
A is the surface area of the sphere 
r is the radius of the sphere 

We know for our problem that A=2122.64 and \pi =3.14, so lets replace those vales in our formula:
A=4 \pi r^2
2122.64=4(3.14)r^2
2122.64=12.56r^2
Now, we just need to solve our equation for r:
\frac{2122.64}{12.56} =r^2
r^2=\frac{2122.64}{12.56}
r^2=169
r=+or- \sqrt{169}
r=13 or r=13
Since the radius of a sphere cannot be a negative number, r=13.

We can conclude that the radius of a sphere with surface area <span>2,122.64 </span>in^2 is 13 in.
3 0
2 years ago
Graph f(x) = 2x^4+3 <br> let x = 0, 1, and 2.<br> please show your work
mestny [16]
Sub those points for x
f(x) is the y

(x,y)

so for x=0
f(0)=2(0)^4+3
f(0)=0+3
f(0)=3
(0,3) is a opint

for x=1
f(1)=2(1)^4+3
f(1)=2(1)+3
f(1)=2+3
f(1)=5
(1,5) is another point

for x=2
f(2)=2(2^4)+3
f(2)=2(16)+3
f(2)=32+3
f(2)=35
(2,35) is another point


points are
(0,3)
(1,5)
(2,35)
3 0
2 years ago
WILL MARK BRAINLIEST CAR!!!! HELP
Digiron [165]

Answer:

111°

Step-by-step explanation:

Let the centre of the circle be C

mRQ=157 (marked)

The angle at the centre of a circle standing on an arc is twice any angle at the circumference, standing on the same arc. So <SCR=2(SQR)=2(46)=92. mSR=<SCR=92

All the arc measure add up to 360 so:

mSQ+mRQ+mSR=360

mSQ+157+92=360

mSQ=360-249=111

4 0
3 years ago
Find the value of d such that the system of equations
vova2212 [387]

Answer:

18x okkklllkkkkkkkkkkkkkkkkkkkkkkkkkkmmm

4 0
3 years ago
-3(3x-8) apply distributive property
madreJ [45]

Answer:

-9x+24

Step-by-step explanation:

Multiply using the distributive property. Hope this helps :)

3 0
2 years ago
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