Answer:
Step-by-step explanation:
As per the graph, the y-intercept is 20 which is the initial amount.
Another marked point has coordinates (4, 50).
<u>The slope is:</u>
<u>The equation of the line is:</u>
$20 is the initial deposit and weekly deposit is $7.5
The student will have $135 in her bank account at the end of the ninth week. You can fine this out by finding out the amount she deposits a week and to do this you would take the $30 and divide it by 2 because she had $30 at the end of the second week.
30/2=15
So you see that the student deposits $15 each week, so to find out how much money she will have in 9 weeks you will multiply her $15 by 9.
15x9=135
So the student will have $135 at the end of the ninth week.
The problem cannot be fully solved because you did provide the line on which the line is parallel/ but i can give you the steps on how to solve it. first solve the slope of the parallel line by
m = ( y2 - y1 ) / ( x2 - x1 )
then the slope of that line is equal to slope of line passing pooint ( -1 , 1)
then solve the y intercept of the line using
y = mx + b
where b is the y intercept
then you will have the equation of the line
Answer:
x = 0.
Step-by-step explanation:
(-35)^x = 1
Now any number to the power 0 is 1.
So x = 0.
To find q + 3, you need to answer this first:
What is 5-3?
5-3=2.
q would be equal to 2.
so now we have something like this:
1
_ ( 2 + 3) =5
3
