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salantis [7]
4 years ago
11

What is the solution to the system of linear equations?

Mathematics
1 answer:
soldier1979 [14.2K]4 years ago
8 0

Answer:

x =  -5

y = -8

Step-by-step explanation:

Given

-8x - 7y = 96

-3x + 5y = -25

Required

Determine x and y

Make y the subject  of formula in the second equation

-3x + 5y = -25

5y = 3x - 25

y = \frac{3}{5}x - \frac{25}{5}

y = \frac{3}{5}x - 5

Substitute this value in the first equation

-8x - 7(\frac{3}{5}x - 5) = 96

-8x - 7*\frac{3}{5}x + 7 * 5 = 96

-8x - \frac{21}{5}x + 35 = 96

Collect Like Terms

-8x - \frac{21}{5}x = 96 - 35

\frac{-61}{5}x = 61

x = 61 * \frac{-5}{61}

x =  -5

Recall that

y = \frac{3}{5}x - 5

This gives

y = \frac{3}{5} * -5 - 5

y = -3 - 5

y = -8

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Step-by-step explanation:

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63000rate = 378000

rate= 378000/63000

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Please help finding the volume of the cylinder. Extra points and brainiest will be given.
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Step-by-step explanation:

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Suppose that 30% of all students who have to buy a text for a particular course want a new copy (the successes!), whereas the ot
Softa [21]

Answer:

a. Mean = 4.5, Standard Deviation = 1.775

b. 0.0152

Step-by-step explanation:

Given

n = 15 purchasers

p = Success = 30%

p = 0.3

q =Failure = 70%

q = 0.7

a.

Mean = np

Mean = 15 * 0.3

Mean = 4.5

Standard Deviation = √Variance

Variance = npq

Variance = 15 * 0.3 * 0.7

Variance = 3.15

Standard Deviation = √3.15

Standard Deviation = 1.774823934929884

Standard Deviation = 1.775 ---------- Approximated

b.

The probability that the number who want new copies is more than two standard deviations away from the mean value

Standard Deviation = 1.775

Mean = 4.5

2 Standard Deviation and Mean = 2 * 1.775 + 4.5

= 3.55 + 4.5

= 8.05

P(X>8.05) = P(9) + P(10) +........+ P(15)

Using the binomial distribution

(p + q) ^ n where p = 0.3, q = 0.7 , n = 15

Expanding (p+q)^n where n = 15 and r > 8

We have

15C9 p^9 q^6 + 15C10 p^10 q^5 + 15C11 p^11 q⁴ + 15C12 p^12 q³ + 15C13 p^13 q² + 15C14 p^14 q + p^15

= 5005 (0.3)^9 (0.7)^6 + 3003 (0.3)^10 (0.7)^5 + 1365 (0.3)^11 (0.7)⁴ + 455 (0.3)^12 (0.7)³ + 105 (0.3)^14 (0.7)² + 15 (0.3)^14 (0.7) + 0.3^15

=0.015234

7 0
4 years ago
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