Answer:
x = 6
Step-by-step explanation:
<em>If </em><em>two secants</em><em> are drawn from</em><em> a point outside </em><em>the circle, then the </em><em>product</em><em> of the lengths of</em><em> one secant </em><em>and its</em><em> external segment</em><em> equals the </em><em>product </em><em>of the lengths of</em><em> the other secant </em><em>and its</em><em> external segment</em><em> </em>
Let us solve the question.
∵ There is a circle in the given figure
∵ There are two secants intersected at a point outside the circle
∵ The length of one of them = 8
∵ The length of its external segment = x
∵ The length of the other secant = 4 + 8 = 12
∵ The length of its external segment = 4
→ By using the rule above
∴ 8 × x = 12 × 4
∴ 8x = 48
→ Divide both sides by 8
∴ x = 6
D because n= -14 and were dividing 56
Expand
Simplify 0.9x + 1.26 - 2.3 + 0.1 * x to x - 1.04
add 1.04 to both sides
simplify 1.6 + 1.04 to 2.64
Answer: x = 2.64
Answer:
y = 
x + 8
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
y = - 3x + 13 is in this form
with m = - 3
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - 
=
y = x + c ← is the partial equation
To find c substitute (6, 10) into the partial equation
10 = 2 + c ⇒ c = 10 - 2 = 8
y = x + 8 ← equation of line
Answer:
Yes
Step-by-step explanation:
