All categories

3 years ago

The parent function is f(x)=2^x-1 +3 and the new function is g(x)=2^x+2 +5

Mathematics

1 answer:

ratelena [41]3 years ago

6 0

Answer:

B and C

Step-by-step explanation:

There are two ways of looking at this question. You can do it algebraically or you can make a graph that will give you the answer visually.

Graph

I'll try to do both. First the graph. (See below)

The red line is f(x)
The blue line is g(x)

The graph tells us that the line is shifted

2 units up (blue is above red) and
3 units to the left (blue is to the left of red)

Algebra.

g(x) = 2^[(x - 1) + 3] + 3 (+ 2)

The rewrite shows that +3 means left. +2 means up.

You might be interested in

What is the answer to this 5 ( y + 8)

konstantin123 [22]

Answer:

ijsdbf

dsad

Stepdvds-by-step explanation:

5 0

3 years ago

Read 2 more answers

50 POINTS STUCK

hram777 [196]

Answer:

C. 62.8 units

Step-by-step explanation:

Use distance formula or Pythagorean theorem.

Pythagorean-

6^2+8^2= radius^2

100= radius^2

10= radius

radius= r

Use circumference formula.

C=2pir

C=2pi10

C=62.83

7 0

3 years ago

How does f(t) change over the interval from t = 7 to t = 8?<br>A f(t)

denis23 [38]

Answer:

you have you have and equation and then plug 7,8 into t and you get your awnser

Step-by-step explanation:

get your equationn by Reding the graph or table then to y2 minus y1 over x2 minus x1 and then look at the graph for the y-int and but then , in to t

5 0

3 years ago

23=x-9;x=14 burgers and fries

goblinko [34]

I'm assuming you're solving for x.

23=x-9
x-32=0
x=32

5 0

3 years ago

Read 2 more answers

In 2011, New York City has a total of 11,232 motor vehicle accidents that occurred on Monday through Friday between the hours of

cestrela7 [59]

Answer:

$a. \ P(X=0)=5.574\times10^{-7}$

$b. \ \ P(X\leq 1)=8.584\times10^{-6}$

$c.\ \ \ P(X\geq 4)=0.9997$

Step-by-step explanation:

a. #We notice this is a Poisson probability function expressed as:

$f(x)=\frac{\mu^xe^{-\mu}}{x!}$

x-number of occurrences in a given interval.

$\mu$ -mean occurrences of the event

-The mean is calculated as:

$\mu=\frac{14.4}{4}=3.6$

#the probability of no accidents in a 15-minute period is :

$P(x)=\frac{\mu^xe^{-\mu}}{x!}\\\\P(X=0)=\frac{14.4^0e^{-14.4}}{0!}\\\\=5.574\times10^{-7}$

Hence, the probability of no accident in a 15-min period is $=5.574\times10^{-7}$

b. The the probability of at least one accident in a 15-minute period. is calculated as:

$P(x)=\frac{\mu^xe^{-\mu}}{x!}\\\\P(X\leq 1)=\frac{14.4^0e^{-14.4}}{0!}+\frac{14.4^1e^{-14.4}}{1!}\\\\=5.574\times10^{-7}+8.026\times 10^{-6}\\\\=8.584\times 10^{-6}$

Hence, the probability of at least one accident in a 15-minute period is $8.584\times10^{-6}$

c. The probability of four or more accidents in a 15-minute period is calculated as:

$P(X\geq 4)=1-P(X\leq 3)=1-[P(X=0)+P(X1)+P(X=2)+P(X=3)]\\\\=1-[5.574\times10^{-7}+a. \ 8.026\times10^{-6}+\frac{14.4^2e^{-14.4}}{2!}+\frac{14.4^3e^{-14.4}}{3!}]\\\\=1-[8.584\times 10^{-6}+5.779\times10^{-5}+2.774\times10^{-4}]\\\\=0.9997$

Hence,the probability of four or more accidents in a 15-minute period. is 0.9997

7 0

2 years ago