Answer:
p = 0.38, n = 20
The probability that he throws more than 10 strikes = 0.09233
Step-by-step explanation:
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of times Jack wants to bowl = 20
x = Number of successes required = number of strikes he intends to get
p = probability of success = probability that Jack throws a strike = 0.38
q = probability of failure = probability that Jack doesn't throw a strike = 0.62
P(X > x) = Σ ⁿCₓ pˣ qⁿ⁻ˣ (summing from x+1 to n)
P(X > 10) = Σ ²⁰Cₓ pˣ qⁿ⁻ˣ (summing from 11 to 20)
P(X > 10) = [P(X=11) + P(X=12) + P(X=13) + P(X=14) + P(X=15) + P(X=16) + P(X=17) + P(X=18) + P(X=19) + P(X=20)
P(X > 10) = 0.09233
There are binomial distribution cacalculators that can calculate all of this at once. Get one to minimize errors.
2x2x2x2x2=32
32x2=64
2x2x2x2x2x2=64
2^6 is your answer
Answer:
The probability is 0.0052
Step-by-step explanation:
Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:
P(A/B) = P(A∩B)/P(B)
The probability P(B) that at least three are aces is the sum of the following probabilities:
- The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
- There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

So, the number of ways to select exactly 3 aces is:

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725
Then, the probability P(B) that at least three are aces is:

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:
P(A∩B) = 1/270,725
Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

Answer:
<em>The price is the same at both stores for 2 prints.</em>
Step-by-step explanation:
<u>Equations</u>
Let's set the variable
x = number of photo prints
Company Photo Plus charges $2 for each print and $6 for a processing fee, thus the total charges are:
PP = 6 + 2x
Company Picture Time charges $3 for each print and $4 for a processing fee, thus it charges a total of:
PT = 4 + 3x
It's required to find the number of prints that make both stores charge the same. Equating both functions:
6 + 2x = 4 + 3x
Subtracting 2x and 4:
x = 2
The price is the same at both stores for 2 prints.
Answer:
The solution of system of equation is (-2,0)
Step-by-step explanation:
Given system of equation are
Equation 1 : 2x+y=(-4)
Equation 2 : y+
x=(-1)
To plot the equation of line, we need at least two points
For Equation 1 : 2x+y=(-4)
Let x=0
2x+y=(-4)
2(0)+y=(-4)
y=(-4)
Let x=1
2x+y=(-4)
2(1)+y=(-4)
y=(-6)
Therefore,
The required points for equation is (0,-4) and (1,-6)
For Equation 2 : y+
x=(-1)
Let x=0
y+
x=(-1)
y+
(0)=(-1)
y=(-1)
Let x=2
y+
x=(-1)
y+
(2)=(-1)
y=(-2)
The required points for equation is (0,-1) and (2,-2)
Now, plot the graph using this points
From the graph,
The red line is equation 1 and blue line is equation 2
Since. The point of intersection is solution of system of equations
The solution of system of equation is (-2,0)