Answer:
We can see that this is dependent probability. We can find dependent probability of happening event A then event B by multiplying probability of event A by probability of event B given that event A already happened.
Step-by-step explanation:
In our case event A is pirate hitting captain's ship and event B is captain missing pirate's ship. We have been given that pirate shoots first so pirate's ship can't be hit before pirate shoots his cannons. So probability of hitting captain's ship is 1/3. We have been given that if Captain Ben's ship is already hit then Captain Ben will always miss. So the probability of Captain missing the dread pirate's ship given the pirate Luis hitting the Captain ship is 1. Now to find probability that pirate hits Captain, but Captain misses we will multiply our both probabilities.
Answer:
3rd option
Step-by-step explanation:
- 10 ≥ 6x - 4 ( add 4 to both sides )
- 6 ≥ 6x , then
6x ≤ - 6 ( divide both sides by 6 )
x ≤ - 1
Thus x = - 1 is a solution to the inequality
Answer:
Part A
Eagle = 6 lbs * 60%
= 6 * 0.6
= 3.6 pounds
Bear = 105 lbs * 25%
= 105 * 0.25
= 26.25 pounds
3.6 + 26.25 = 29.85 pounds
Part B
Percent Increase = Change/Original * 100
= 10/105 * 100
= 9.52%
Step-by-step explanation:
hope this helps bye
S(-6, 4)
If you plot on a simple graph you will find the other end point S there
Answer:
19/25
Step-by-step explanation:
