Answer:
Step-by-step explanation:
Average speed = distance/time
Trip to dry dock
Let x be the velocity
Time = 2hours
Distance = average speed ×time
Distance = x×2
Distance = 2x
Return trip
Velocity = x-5 (5 miles per hour faster on the trip there than on the return trip)
Time = 3hrs
Distance = 3(x-5)
Since the distance is the same both to and fro;
2x = 3(x-5)
2x = 3x -15
2x-3x = -15
-x = 15
x = 15
Hence the aircraft carrier's average speed on the outbound trip is 15miles/hour
Answer:
23/96 = about 24%
Step-by-step explanation:
42 + 23 + 31 = 96 students total in survey
23 students that like volleyball / total students =23.95% about 24%
Answer:
868.065
Step-by-step explanation:
198.040 ÷ 98.1 + 100 x 4.3
= 2.0188 + 100 x 4.3
= 201.8756 x 4.3
= 868.065
Place a dot on the 0 spot and draw an arrow facing to the right. The dot must not be filled in. This shows that x>0 because the arrow and dot show the numbers that x can be.
Answer:
give simplify + 1 2+ h find 2