Answer:
The answer is that it is a speaker note.
Explanation:
It leaves a note for people that use presentation files. I use it all the time on my google slides.
Program p1;
var a,b,c,d : integer; {i presume you give integer numbers for the values of a, b, c }
x1, x2 : real;
begin
write('a='); readln(a);
write('b='); readln(b);
write('c=');readln(c);
d:=b*b - 4*a*c
if a=0 then x1=x2= - c/b
else
if d>0 then begin
x1:=(-b+sqrt(d)) / (2*a);
x2:=(-b - sqrt(d))/(2*a);
end;
else if d=0 then x1=x2= - b /(2*a)
else write ("no specific solution because d<0");
writeln('x1=', x1);
writeln('x2=',x2);
readln;
end.
Answer:
While loops are typically used when you don’t know how many times the loop needs to repeat. The body of the loop will repeat while the condition is true. The logical expression will be evaluated just before the body of the loop is repeated.
Let’s say that we want to find the square root of a number. For some square roots, you’re never going to be exact. Let’s say that we want to find a square root that, when multiplied by itself, is within 0.01 of the square we want. How do we do it? There’s a really old process that we can apply here.
Start by guessing 2.
Compute the guess squared.
Is the guess squared close to the target number? If it’s within 0.01, we’re done. We’ll take the absolute value of the difference, in case we overshoot. (In Python, abs is the absolute value function.)
If it’s not close enough, we divide the target number by our guess, then average that value with our guess.
That’s our new guess. Square it, and go back to Step #3.
Explanation:
Czarnowski and Triantafyllou learned that boat propellers are not very efficient, except penguin propulsion systems.
I believe that the three procedures are...
1. Sub - Standard sub routine
2. Function - a routine that returns an answer
3. Property - reserved for <span> Class Modules</span>
<span>Hope this helps, please mark brainliest!</span>
