Question

The square and the triangle have equal perimeters find the value of x find the perimeter

Answer 1

I hope this helps you

Answer 2

Answer:  The required value of x is 10 and the perimeter is 28.

Step-by-step explanation:  Given that the square and the triangle have equal perimeters.

We are to find the value of x and the perimeter.

From the given figure, we note that

length of a side of the square, a = x-3

and the lengths of the sides of the triangle are x, x and 8.

According to the given information, we get

$4a=x+x+8\\\\\Rightarrow 4(x-3)=2x+8\\\\\Rightarrow 4x-12=2x+8\\\\\Rightarrow 4x-2x=8+12\\\\\Rightarrow 2x=20\\\\\Rightarrow x=\dfrac{20}{2}\\\\\Rightarrow x=10.$

Also, the perimeter of the square and the triangle is

$4(x-3)=4(10-3)=4\times7=28$

Thus, the required value of x is 10 and the perimeter is 28.