It's D, it's the only one where it has a -6 at the end other than A, but if you look at the A when distributed there isn't a 23x<span />
Answer:
Verified
Step-by-step explanation:
Let the diagonal matrix D with size 2x2 be in the form of
![\left[\begin{array}{cc}a&0\\0&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%260%5C%5C0%26d%5Cend%7Barray%7D%5Cright%5D)
Then the determinant of matrix D would be
det(D) = a*d - 0*0 = ad
This is the product of the matrix's diagonal numbers
So the theorem is true for 2x2 matrices
Answer:
Put a dot on 7 on the y axis then draw a horizontal line through y=7
Step-by-step explanation:
Answer:
show this
and plz mark as brainlist
2(3x+5)=9x+9-3x+1
(2)(3x)+(2)(5)=9x+9-3x+1
6x+10=9x+9-3x+1
6x+10=(9x-3x)+(9+1)
6x+10=6x+10
6x-6x+10=6x-6x+10
10=10
10-10=10-10
0=0
All real numbers are solutions.
