Question

Daniel collects baseball cards and keeps them in a special binder. Each page holds 9 baseball cards in a 3x3 array. The first page is four ninths full. The second page is one third full. If daniel put all the cards onto just one page what fraction of that page would be full.

Answer 1

Answer: The fraction of that page would be full=$\frac{7}{9}$

Step-by-step explanation:

Given: Daniel collects baseball cards and keeps them in a special binder.

The first page is four ninths full$=\frac{4}{9}\times9=4$

Thus, there are 4 cards on the first page.

The second page is one third full$=\frac{1}{3}\times9=3$

Thus, there are 3 cards on the second page.

If daniel put all the cards onto just one page , then the total cards on on one page= 3+4=7

The fraction of that page would be full=$\frac{7}{9}$