Answer:
So, I believe n/2 may be even and 3n+1 is odd. They succumb to 3n if that helps.
Step-by-step explanation:
I'm not certain on what to do but I hope this helps some what.
Answer:
A
![f(x+ h) = 6x + 6h -3](https://tex.z-dn.net/?f=f%28x%2B%20h%29%20%20%3D%20%206x%20%2B%206h%20-3)
B
![f(x+ h) - f(x) = 6h](https://tex.z-dn.net/?f=f%28x%2B%20h%29%20-%20%20f%28x%29%20%3D%20%20%206h)
C
![\frac{f(x + h) - f(x)}{h} = 6](https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%20%2B%20h%29%20-%20f%28x%29%7D%7Bh%7D%20%20%20%3D%20%206)
Step-by-step explanation:
From the question the given equation is
![f(x) = 6x -3](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%206x%20-3)
Considering A
![f(x+ h) = 6(x + h) -3](https://tex.z-dn.net/?f=f%28x%2B%20h%29%20%20%3D%20%206%28x%20%2B%20h%29%20-3)
=> ![f(x+ h) = 6x + 6h -3](https://tex.z-dn.net/?f=f%28x%2B%20h%29%20%20%3D%20%206x%20%2B%206h%20-3)
Considering B
![f(x+ h) - f(x) = 6x +6h -3 - (6x-3)](https://tex.z-dn.net/?f=f%28x%2B%20h%29%20-%20%20f%28x%29%20%3D%20%206x%20%2B6h%20-3%20-%20%286x-3%29)
![f(x+ h) - f(x) = 6h](https://tex.z-dn.net/?f=f%28x%2B%20h%29%20-%20%20f%28x%29%20%3D%20%20%206h)
Considering C
![\frac{f(x + h) - f(x)}{h} = \frac{6h}{h}](https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%20%2B%20h%29%20-%20f%28x%29%7D%7Bh%7D%20%20%3D%20%20%5Cfrac%7B6h%7D%7Bh%7D)
![\frac{f(x + h) - f(x)}{h} = 6](https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%20%2B%20h%29%20-%20f%28x%29%7D%7Bh%7D%20%20%20%3D%20%206)
15 is answer for the missing side
answer : am/b
Step-by-step explanation:
the rate of copying packets = a/b
each packet (a) contains *m* pages
total number of pages in all books together is =a×m
so the rate of copying of pages = a×m/b
Answer:
Probability of not having homework tonight is ![\frac{5}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7D)
Step-by-step explanation:
Given that the probability of having homework tonight is
. we have to find the probability of not having homework tonight.
As total probability is 1 i.e
P(occurring an event)+P(not occurring an event)=1
⇒ P(having homework tonight)+P(not having homework tonight)=1
⇒
+P(not having homework tonight)=1
⇒ P(not having homework tonight)= ![1-\frac{1}{6}=\frac{5}{6}](https://tex.z-dn.net/?f=1-%5Cfrac%7B1%7D%7B6%7D%3D%5Cfrac%7B5%7D%7B6%7D)
Hence, Probability of not having homework tonight is ![\frac{5}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7D)