Answer:
Step-by-step explanation:
Given that,
XY//BD and XB=XC
Since, XB = XC, then ∆XBC is an isosceles triangle with angle <B = <C.
A. If an angle occupy the same relative position at each intersection where a straight line crosses two others straight lines. If the two straight lines are parallel, then the corresponding angles are equal.
To check for corresponding angle: look at if the shape form "F" shape and be sure that the lines that form the "F" shape are parallel.
So, to complete the statement,
Angle XBC = 55° because it a corresponding angle to AXY
They form a "F" and XY//BD
B. To find BXC
We know that triangle BXC is an isosceles triangle
The sum of angle in a triangle is 180°
Then,
XBC + BCX + BXC = 180°
Since, ∆XBC is isosceles then, angle <XBC = < BCX = 55°
Then,
XBC + BCX + BXC = 180°
55 + 55 + BXC = 180°
110 + BXC = 180°
BXC = 180° - 110
BXC = 70°
