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4 years ago

One angle measure in an acute triangle is 38°. What could the measure of one of the other angles be?

Mathematics

2 answers:

Ksju [112]4 years ago

6 0

One of the angles as your answer is 69 degrees

Oksi-84 [34.3K]4 years ago

3 0

If is an acute triangle, all the angles should be acute angles.
180-38=142°
142-69=73°
So your answer is 69°, lovely~

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Trevor is painting a mural on a 1-square-meter section of a wall. He has completed a rectangular part of the mural that is 34 me

goblinko [34]

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3 years ago

[(M^2N^2-MN)(M^2N^2+MN)]/MN

GaryK [48]

Answer:

Step-by-step explanation:

M²N² - MN = MN (MN - 1)

M²N² + MN = MN (MN + 1)

$\frac{(M^{2}N^{2}-MN)(M^{2}N^{2}-MN)}{MN}= \frac{MN(MN-1) * MN(MN + 1)}{MN}\\$

= (MN - 1) * MN * (MN + 1)

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3 years ago

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5 0

3 years ago

Read 2 more answers

Expand.<br> Your answer should be a polynomial in standard form.<br> (3c + 2)(c^2-6c-4)

evablogger [386]

Answer:

After expanding the polynomial $(3c + 2)(c^2-6c-4)$ we get $3c^3-16c^2-24c-8$

Step-by-step explanation:

We need to expand the polynomial $(3c + 2)(c^2-6c-4)$

Multiply the terms:

$(3c + 2)(c^2-6c-4)\\=3c(c^2-6c-4)+2(c^2-6c-4)\\=3c^3-18c^2-12c+2c^2-12c-8\\=3c^3-18c^2+2c^2-12c-12c-8\\=3c^3-16c^2-24c-8$

So, after expanding the polynomial $(3c + 2)(c^2-6c-4)$ we get $3c^3-16c^2-24c-8$

3 0

3 years ago

Point that satisfies

Kobotan [32]

Answer: D. (4,4)

Step-by-step explanation:

1. You have the following expression:

$y\leq x^{2}-3x+2$

3. To find the point that satifies the expression shown above, you only need to substitute each one of them into the expression, as you can see below:

A. $3\leq 3^{2}-3(3)+2\\3\leq 2$ (This is not true)

B. $2\leq 2^{2}-3(2)+2\\2\leq 0$ (This is not true)

C. $1\leq 1^{2}-3(1)+2\\1\leq 0$ (This is not true)

D. $4\leq 4^{2}-3(4)+2\\4\leq 6$ (This is true)

4. Therefore, the correct answer is the option D, which is: (4,4)

6 0

3 years ago