Question

I need help with this problem

Answer 1

Answer:

$3.\ \dfrac{3x}{11x}, \dfrac{6}{22}, \dfrac{9}{33},\dfrac{12}{44}$

$4. -18\\5.\ 400$

Step-by-step explanation:

Solution 3:

Equivalent fractions to are to $\frac{3}{11}$ be found out.

Method: By Multiplying both the denominator and numerator with the same number, we can easily find equivalent fractions.

1. Multiply with 2:

$\dfrac{3 \times 2}{11 \times 2}\\\Rightarrow \dfrac{6}{22}$

2. Multiply with 3:

$\dfrac{3 \times 3}{11 \times 3}\\\Rightarrow \dfrac{9}{33}$

3. Multiply with 4:

$\dfrac{3 \times 4}{11 \times 4}\\\Rightarrow \dfrac{12}{44}$

If we try to write in variable form, it can be written as:

$\dfrac{3x}{11x}$

where x is any number.

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Solution 4:

$(2x-10)$ when $x=-4$

$2 \times (-4) -10\\\Rightarrow -8 -10\\\Rightarrow -18$

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Solution 5:

$(10a)^2, a=-2\\\Rightarrow \{10 \times (-2)\}^2\\\Rightarrow (-20)^2\\\Rightarrow 400$