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DaniilM [7]
3 years ago
14

Simplify (x⁴)³ ??????

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
3 0

Rule:

(xᵃ)ᵇ = x⁽ᵃ * ᵇ⁾

(x⁴)³ = x⁽⁴ * ³⁾ = x¹²

You might be interested in
Is there a faster way to find GCF of large numbers e.g 828 and 529.
Sunny_sXe [5.5K]
You can use prime factorization to find the GCF of a set of numbers. This often works better for large numbers, where generating lists of all factors can be time-consuming.
Here’s how to find the GCF of a set of numbers using prime factorization:
* List the prime factors of each number.
* Circle every common prime factor — that is, every prime factor that’s a factor of every number in the set.
* Multiply all the circled numbers.
The result is the GCF.
For example, suppose you want to find the GCF of 28, 42, and 70. Step 1 says to list the prime factors of each number. Step 2 says to circle every prime factor that’s common to all three numbers (as shown in the following figure).
As you can see, the numbers 2 and 7 are common factors of all three numbers. Multiply these circled numbers together:
2 · 7 = 14
Thus, the GCF of 28, 42, and 70 is 14.

5 0
2 years ago
I really need help with this!!! someone help please
Minchanka [31]

Answer:

156 in squared

Step-by-step explanation:

So the formulas will be stated below

Parallelogram Area= 1/2h(b1+b2)

Square Area= Bh

So first do

(4)(12+6)

(4)(18)

No need to half it bc there's the same shape at the bottom

72+18+30+36

6(3)

3x5(2)

12(3)

5 0
3 years ago
a fish tank at a pet store has 8 zebra fish in how many different way s can nikki choose 3 zebra fish to buy
liraira [26]
This is 8C3.
8!/5!3!=8X7X6/3X2X1=56 ways
6 0
3 years ago
Read 2 more answers
There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit
Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a \frac{3}{11} chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is \frac{8}{11}, and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is\frac{2}{11}, and the probability of picking the second red ball is \frac{1}{10} and the probability of picking the green ball is\frac{1}{9}. We want to multiply thm again, as per the multiplication rule like the last problem.

\frac{2}{11}*\frac{1}{10}*\frac{1}{9}=\frac{1}{11*5*9}=\frac{1}{495}

5 0
3 years ago
write an equation in y=mx+b for a line that passes through (3,-4) & has a slope of -3. you can write it in point-slope and c
dedylja [7]
Y = -3x + b
Plug in point
-4 = -3(3) + b
-4 = -9 + b, b = 5
Solution: y = -3x + 5
5 0
3 years ago
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