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Alexeev081 [22]
3 years ago
12

Jessie says to round 763,400 to the nearest ten thousand, he will round to 770,000 is he right ? explain

Mathematics
2 answers:
nlexa [21]3 years ago
5 0
No he is not right because if you would look to the right 3 is smaller than the number 5 so you have to round down therfore that answer is 760000
weqwewe [10]3 years ago
3 0

For this case we have the following definition:

ten thousand place: number of five digits whose absolute value is greater than zero.

Then, we have the following rounding rule:

1) If the previous number is greater than or equal to five, then the next number increases by one unit.

2) If the previous number is less than or equal to five, then the next number remains the same.

We then have the following number:

763,400

Rounding to the nearest ten thousand we have:

760,000

Answer:

Jessie is wrong. The correct answer is:

760,000

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Find mean, median and mode of 140, 130, 90, 80, 60, 50, 30, 20, 10, 0
Alecsey [184]
For the mean you would have to add up all the numbers up and divide by the amount of numbers. For your problem you would get 610/10= 61. 

For the median you would arrange all the numbers in order from least to greatest and cancel one from the left and one from the right each time. Since there is no middle number, the closest would be 50 and 60. Thus you you add 50+60 and get 110 and then divide by 2 giving you 55.

For the mode, there is no mode because none of the numbers repeat more than once.

I hope this clarifies your doubt. :)
3 0
3 years ago
(02.02 HC)
Dima020 [189]
Hey there!

It seems as if you found the answer to your problem?  If you need any help though, just let me know!

Let me know if you'd like me to explain how I got this answer!
3 0
3 years ago
The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi
kondaur [170]

Answer:

0.9

0.3012

0.1809

230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

= 1 - e^-0.1

= 1 - 0.1

= 0.9

b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

= 0.3011942 = 0.3012

c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

= 1 - e-^-0.6

= 1 - 0.5488116

= 0.4511883

P(X < 100000) = 1 - e^-λx

x = 100000

P(X < 60,000) = 1 - e^-(0.00001 * 100000)

= 1 - e^-1

= 1 - 0.3678794

= 0.6321205

Hence,

0.6321205 - 0.4511883 = 0.1809322

d. Find the 90th percentile. So 10 percent of the TV sets last more than what length of time?

P(x > x) = 10% = 0.1

P(x > x) = e^-λx

0.1 = e^-0.00001 * x

Take the In

−2.302585 = - 0.00001x

2.302585 / 0.00001

= 230258.5

3 0
3 years ago
How much will the guitar be worth in 10 years?
Contact [7]

Answer:

$44487

Step-by-step explanation:

If you plug in 10 for t, you are left with the following equation:

V=12000(1.14)^{10}=12000\cdot 3.7072\approx 44487. Hope this helps!

8 0
3 years ago
Read 2 more answers
Suppose you know that ∠S and ∠Y are complementary, and that m∠S = 2(m∠Y) − 60°. Find m∠Y.
hodyreva [135]

Answer:

m∠Y=50°

Step-by-step explanation:

So, we know that ∠S+∠Y=90 and that m∠S=2(m∠Y)-60.

If you plug those things into the equation, you get (2[m∠Y]-60)+m∠Y=90.

Then you multiply 2 and m∠Y: 2m∠Y-60+m∠Y=90.

Combine like terms: 3m∠Y-60=90.

Then you add 60 to both sides: 3m∠Y=150

Divide 3 on both sides: 3∠Y=50

7 0
3 years ago
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