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Nataly [62]
3 years ago
12

Mr. Hardy built a fenced-in area for his children in the shape of a square with each side 75 feet in length. Find the distance o

f the diagonal path from one corner to the opposite corner.
Mathematics
1 answer:
8090 [49]3 years ago
3 0

Answer:

75 square root of 2

Step-by-step explanation:

if its a square using 45 45 90 triangle formula it'll be 75 to the the square root of 2

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Review the expression below -2(a+b-5)+3(-5a+2b)+b(6a+b-8)
Oduvanchick [21]

Answer:

6ab + b^2 - 17a - 4b + 10

Step-by-step explanation:

-2(a+b-5)+3(-5a+2b)+b(6a+b-8)

Now we break the parenthesis. To break that, we multiply each of the value inside the parenthesis by the adjacent number. That is, for the first part of the expression, we multiply by -2, then by 3, and then by b.

Algebraic Operations need to be considered:

[ (-) x (-) = (+); (-) x (+) = (-)]

= [-(2*a) + (-2*b) - (-2*5)] + [3*(-5a) + (3*2b)] + [(b*6a) + (b*b) - (b*8)]

= -2a - 2b +10 -15a + 6b + 6ab + b^2 - 8b

Now, we will make the adjustment by the similarity value.

= - 2a - 15a - 2b + 6b - 8b + 6ab + b^2 + 10

= - 17a - 4b + 6ab + b^2 + 10

= 6ab + b^2 - 17a - 4b + 10

Therefore, the answer of the expression is = 6ab + b^2 - 17a - 4b + 10

6 0
3 years ago
Are these angles complementary, supplementary, or neither?
SashulF [63]
I would say complementary because the angle degrees are the same
4 0
3 years ago
Pls, help due in 10 mins! Pls, answer both questions!
vredina [299]

Answer:

Answer for first question is 22 yards!

Step-by-step explanation:

I used to do this, you have to multiply. A way of helping, is to split it in half, then add it all together. Now, I am not always accurate but I hope this helps you!

5 0
2 years ago
Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

5 0
3 years ago
List a time when it might be useful to know the unit rate.
Andrej [43]

Answer:

a good time is when u are in math class and a teacher assigns u a homework of unit rate.

Step-by-step explanation:

3 0
3 years ago
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