A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
No of substes is given by 2^n where n is the no of elements.
Here, n = 3
Therefore, number of subsets = 2^3 = 8
16.2 miles.
Since she paid a $5 tip, the cost for her fare was $23.50. Let x be the number of 0.2-mile increments in the trip:
23.50 = 2.50 + 1 + 0.25(x-1)
This equation comes from the 2.50 home pick-up fee; $1 for the first 0.2-mile increment; and 0.25 for each other 0.2-mile increment.
Using the distributive property, we have:
23.50 = 2.50 + 1 + 0.25*x - 0.25*1
23.50 = 2.50 + 1 + 0.25x - 0.25
Combining like terms,
23.50 = 0.25x + 2.75
Subtracting 2.75 from both sides, we have:
23.50 - 2.75 = 0.25x + 2.75 - 2.75
20.25 = 0.25x
Dividing both sides by 0.25, we have:
20.25/0.25 = 0.25x/0.25
81 = x
This means there are 81 0.2-mile increments in her trip. 81(0.2) = 16.2 miles
65.52 will be the answer
Work: (10.4 * 12.6) ÷ 2
Answer:
x ≈ 50.76
Step-by-step explanation:
Sin72º = 
200Sin72º
x ≈ 50.76
Hope this is helpful :')
