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3 years ago

Help me find the range of this function please

Mathematics

1 answer:

lara31 [8.8K]3 years ago

8 0

Answer:

{-2, -14, -26, -50}

Step-by-step explanation:

The range of the function is the function evaluated at each point of the given domain. So to find the range of the function we need to find the value of the function for each point in the domain:

- For x = -8

$f(x)=-2x-18$

$f(-8)=-2(-8)-18$

$f(-8)=16-18$

$f(-8)=-2$

The first value of the range of the function is -2

- For x = -2

$f(x)=-2x-18$

$f(-2)=-2(-2)-18$

$f(-2)=4-18$

$f(-2)=-14$

The second value of the range is -14

- For x = 4

$f(x)=-2x-18$

$f(4)=-2(4)-18$

$f(4)=-8-18$

$f(4)=-26$

Th third values of the range is -26

- For x = 16

$f(x)=-2x-18$

$f(16)=-2(16)-18$

$f(16)=-32-18$

$f(16)=-50$

The fourth and last value of the range is -50

Now we can put all the values of the range together

The range of the function is {-2, -14, -26, -50}

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The linear equation of the function is: $g(P) = 22.9P+7$ .
The inverse function is: $g^{-1}(c) = \frac{1}{22.9}(c - 7)$ .
A practical domain is from 0% to 100%
A practical range is from 7 to 29.9

A. Input quantity

The input quantity is the percentage of frozen citrus crop

B. Output quantity

The output quantity is the cost of box of oranges

C. The linear function

We have:

$(P_1,c_1) = (20\%,11.58)\\(P_2,c_2) = (80\%,25.32)$

Calculate the slope of the function

$m = \frac{c_2 - c_1}{P_2 - P_1}$

$m = \frac{25.32 - 11.58}{80\%-20\%}$

$m = \frac{13.74}{60\%}$

$m = 22.9$

The linear equation is calculated as follows:

$c -c_1 = m(P-P_1)$

$c -11.58= 22.9(P-20\%)$

$c-11.58 = 22.9P-4.58$

D. Rewrite as y = mx + b

We have:

$c-11.58 = 22.9P-4.58$

Collect like terms

$c = 22.9P - 4.58 + 11.58$

$c = 22.9P+7$

The function is:

$g(P) = 22.9P+7$

E. A practical domain

The domain is the possible values of P. Because P is a percentage, its possible values are 0% to 100%.

The domain of the function is: $[0\%,100\%]$

F. A practical range

When P = 0%

$c = 22.9 \times 0\% + 7 = 7$

When P = 100%

$c = 22.9 \times 100\% + 7 = 29.9$

Hence, the range of the function is: $[7,29.9]$

G. The meaning of $g^{-1}(12)$

The inverse function of g(P) is $g^{-1}(P)$

So:

$g^{-1}(12)$ is the percentage of frozen citrus crop, when the cost is $12.

H. The inverse formula

We have:

$c = 22.9P+7$

Subtract 7 from both sides

$c - 7 = 22.9P$

Make P the subject

$P = \frac{1}{22.9}(c - 7)$

So, the inverse formula is:

$g^{-1}(c) = \frac{1}{22.9}(c - 7)$

Substitute 12 for c

$g^{-1}(12) = \frac{1}{22.9}(12 - 7)$

$g^{-1}(12) = \frac{1}{22.9} \times 5$

$g^{-1}(12) = 22\%$

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and the $y$ -component is -2.50 m/s, so

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