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2 years ago

8

Which figure shows a reflection of pre-image QRS over the line t?

1 answer:

Igoryamba2 years ago

4 0

Answer:

A, because its reflecting off of the y axis

Step-by-step explanation:

I have proof links, and I took the test

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2a + 3b = 5<br> b = a - 5

Lunna [17]

<h2>1st Equation:</h2>

Answer for A:

$a = \frac{5 - 3b}{2}$

Answer for B:

$b = \frac{5 - 2b}{3}$

<h2>2nd Equation:</h2>

Answer:

$a = b + 5$

<u>hope it helps</u><u>.</u>

5 0

2 years ago

The standard diameter of a golf ball is 42.67 mm. A golf ball factory does quality control on the balls it manufactures. Golf ba

sergiy2304 [10]

THE ANSWER IS A:

This is the function:

f(x)=|42.67-x|.

42.670 -.002 =42.668

42.668 mm to 42.670

Explanation:

Production will be stopped if the difference in diameter is greater than 0.002 mm.

This difference can mean that the golf ball has a diameter more than 0.002 larger than 42.67 mm, or a diameter more than 0.002 smaller than 42.67. This is the reason for using an absolute value function.

Absolute value represents the distance a number is from 0. For this function, we would want only the values where the function is less than 0.002.

4 0

2 years ago

Can i get some help and a good explenation

denis-greek [22]

Answer:

The correct answer is $2,50

Step-by-step explanation:

The unit rate is what we use to determine the price of a single unit, when something is sold in a group, as in this case 5 ounces.

4 0

2 years ago

Read 2 more answers

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

3 years ago

Amanda and Ndiba are selling flower bulbs for a school fundraiser. Customers can buy packages of tulip bulbs and bags of daffodi

Gemiola [76]

Answer is on the attachment. Brainlist pls.

Step-by-step explanation:

5 0

2 years ago