Recall that the derivative of a constant is 0.

$\bf y=x^2-4x+4\implies y=(x-2)^2\implies \stackrel{inverse}{x=(y-2)^2}
\\\\\\
\sqrt{x}=y-2\implies \sqrt{x}+2=y\implies x^{\frac{1}{2}}+2=y
\\\\\\
\cfrac{1}{2}x^{-\frac{1}{2}}+0=\cfrac{dy}{dx}\implies \cfrac{1}{2}x^{-\frac{1}{2}}=\cfrac{dy}{dx}$

5 0

3 years ago

Stephanie is 20 years old and has a base annual premium of 930 and a rating factor of 1.30. what is her total premium?

fredd [130]

Don't listen to the other guy. The ANSWER is A). 1209. Your welcome!

5 0

4 years ago

I need some help pls

Nimfa-mama [501]

Answer is A, basically using the Pythagorean theorem but in a slightly different way, should still get you the same answer.

4 0

3 years ago