I think I'm struggling to find the inverse for this one:

Mathematics

1 answer:

USPshnik [31]3 years ago

5 0

Recall that the derivative of a constant is 0.

$\bf y=x^2-4x+4\implies y=(x-2)^2\implies \stackrel{inverse}{x=(y-2)^2}
\\\\\\
\sqrt{x}=y-2\implies \sqrt{x}+2=y\implies x^{\frac{1}{2}}+2=y
\\\\\\
\cfrac{1}{2}x^{-\frac{1}{2}}+0=\cfrac{dy}{dx}\implies \cfrac{1}{2}x^{-\frac{1}{2}}=\cfrac{dy}{dx}$

You might be interested in

Twice a number divided by 5 gives 4 simple equations

melomori [17]

Answer:

x=10

Step-by-step explanation:

Let the number = x

∴ 2x/5=4

∴2x=5*4

∴2x=20

∴x=20/2

∴x=10

Hope it helps you!

Mark as brainliest if you like it

3 0

3 years ago

Read 2 more answers

Compute the permutations and combinations. 6 P 4 15 30 360

3241004551 [841]

The answer is c.
6 P 4 = 360

7 0

3 years ago

Read 2 more answers

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is: