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natita [175]
4 years ago
6

If the scores of a math test are normally distributed with an average score of 76 and a standard deviation of 5, what percentage

of students scored below a 65?
Mathematics
1 answer:
Afina-wow [57]4 years ago
7 0

Answer:

Step-by-step explanation:

Since the scores of the math test are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = math test scores.

µ = mean score

σ = standard deviation

From the information given,

µ = 76

σ = 5

The probability that a student scored below 65 is expressed as

P(x < 65)

For x = 65

z = (65 - 76)/5 = - 2.2

Looking at the normal distribution table, the probability corresponding to the z score is 0.014

The percentage of students that scored below 65 is

0.014 × 100 = 1.4%

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0.0323 as a fraction
svetoff [14.1K]

Answer:

» \frac{323}{10000}

Step-by-step explanation:

To convert the decimal 0.0323 to a fraction,

just follow these steps:

Step 1: Write down the number as a fraction of one:

0.0323 =  \frac{0.0323}{1}

Step 2: Multiply both top and bottom by 10 for every number after the decimal point:

As we have 4 numbers after the decimal point,

So, we multiply both numerator and denominator by 10000.

Therefore ;

→\frac{0.0323}{1}  =  \frac{(0.0323 \times 10000)}{(1 \times 10000)}  \\  \\→ \frac{323}{10000}

3 0
3 years ago
The product of two positive numbers is 750. The first number is 5 less than the second number. The equation x(x – 5) = 750 can b
bezimeni [28]
Ab=750 and a=b-5, using this value of a in the original equation gives you:

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(b+25)(b-30)=0

b=30 


4 0
4 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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