Answer:
x= 5.6
Step-by-step explanation:
we will need to put the information we currently have into an equation:
10•2•x= 112
then multiply 10•2 which equals 20...then the equation wil turn out like this:
20•x=112
now you will isolate the x... but how?? dividing 20 by itslef.. cancelling it out, and if you do one thing to the other side of the equation, you have to do it to the other...
20/20•x=112/20
you will end up with x= 122/20
you can use a calculator for this step, but to practice long division... (check the screen shot thingie)
hope this helped !! ^^
Answer:
\sqrt{6}
Explanation:
From the given diagram,
Hypotenuse sde = x
Opposite side = \sqrt{3}
Using the SOH CAH TOA identity
Sintheta = opposite/hypotenuse
Sin 45 = \sqrt{3}/x
x = \sqrt{3}/sin45
![\begin{gathered} x\text{ =}\frac{\sqrt[]{3}}{\sin 45} \\ x\text{ = }\frac{\sqrt[]{3}}{\frac{1}{\sqrt[]{2}}} \\ x\text{ = }\sqrt[]{3^{}}\cdot\sqrt[]{2} \\ x\text{ =}\sqrt[]{6} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5Ctext%7B%20%3D%7D%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B%5Csin%2045%7D%20%5C%5C%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B%5Cfrac%7B1%7D%7B%5Csqrt%5B%5D%7B2%7D%7D%7D%20%5C%5C%20x%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B3%5E%7B%7D%7D%5Ccdot%5Csqrt%5B%5D%7B2%7D%20%5C%5C%20x%5Ctext%7B%20%3D%7D%5Csqrt%5B%5D%7B6%7D%20%5Cend%7Bgathered%7D)
Hence the value of x is \sqrt{6}
Answer:
28.108 K.
Step-by-step explanation:
Given: Pressure (P)= 1.2atm
Number of moles (n)= 2.6 moles
Volume (V)= 5.00-L
Now finding the temperature (T).
Formula; T= 
R is a constant factor which makes other factors work together.
There is a numerical value for R which we use is 
∴ Temperature (T)= 
⇒ Temperature (T)= 
∴ Temperature is 28.108 K
First you need to know how many pounds of carbon dioxide you get when burning 1 gallon of gasoline. That number is 19.64 pounds
To get the number of pounds released when entire tank is burned you need to multiply gas tank volume and number of pounds you get when 1 gallon is burned.
17.2 * 19.64 = 337.808
Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
