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EastWind [94]
3 years ago
14

Help , please and thanks

Mathematics
1 answer:
ira [324]3 years ago
5 0

Answer:

891,962,172,409

try that

Step-by-step explanation:

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Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
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vertex:(h,k)

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axis of symmetry:x=h

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axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

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therefore

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the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

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let's simplify it to standard form

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simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

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x\in \mathbb{R}

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y\leqslant 4

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\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

4 0
3 years ago
Can anyone help me ASAP!
TiliK225 [7]

Answer:

17.3 in

Step-by-step explanation:

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