You have some unknown integer

, and you know that adding this and the next two integers,

and

, gives a total of 57.
This means

The task is to find all three unknown integers. Notice that if you know the value of

, then you pretty much know the value of the other three integers.
To find

, solve the equation above:

So if 18 is the first integer, then others must be 19 and 20.
H = 2f / (m+1)
[multiply by (m+1)]
h(m+1) = 2f
[divide by 2]
f = (h (m + 1)) / 2
3b / (b+2) = 12 / (b+2)
[multiply by (b+2)]
3b = 12
[divide by 3]
b = 4
3 / (6x + 1) / 2 = 8 / (x + 4) / 3
[multiply both denominators to mike one denominator]
3 / 8(6x+1) = 8 / 3(x+4)
[expand brackets]
3 / (48x + 8) = 8 / (3x + 12)
[multiply by (48x + 8)]
3 = 8(48x + 8) / (3x+12)
[multiply by (3x+12)]
3(3x +12) = 4(48x + 8)
[simplify]
9x + 36 = 192x + 32
173x = 4
x = 4 / 173
Answer:
95
Step-by-step explanation:
Mode is what is the most frequent number that occurred; 95 occurred the most from the data.
Answer:
The domain is all Real x except x = 2 .
Step-by-step explanation:
(cd)(x) = ( 5 / x-2) * x+3
= 5(x+3)/(x-2)
The domain is all Real x except x = 2 .
(because when x = 2 (cd)(x) is undefined).
AC = 18
BC = 6x
AB = 2x + 4
Write and solve:
18 + 6x + 2x + 4
18 + 8x + 4 = 180
You can solve further:
18 + 8x = 176
8x = 158
x = 19 & 3/4
Not 100% sure what the question is asking, but hopefully this helps.