Answer:
it would be close to 12 ft im not 100% sure though the measurements are a little off
Step-by-step explanation:
hypotenuse is 13
then you have the adjacent = 7
13^2 = 169
7^2= 49
169-49=120
the square root of 121 is 11 wich is fairly close to 120(doesnt have one because its not exact)
there is two extra feet so 11 +2 is 13 but there was a little less then 11 so i had sid roughly around 12
brainliest, please???
36 all together.
22 first
14 second
8 random chosen
A) all first shift:
One is pulled 22/36
Second is pulled 21/35
Third is pulled 20/34
Fourth 19/33
Fifth 18/32
Sixth 17/31
Seventh 16/30
Eighth 15/29
Multiply all those together
Probability of all first shift is 0.010567296996663
(That means it's not happening anytime soon lol)
B) one worker 14/36
Second 13/35
Third 12/34
Fourth 11/33
Fifth 10/32
Sixth 9/31
Seventh 8/30
Eighth 7/29
Multiply all those together
Probability of all second shift is 0.000099238805645
(That means it's likely to see 100x more picks of all first shift workers before you see this once.. lol)
C) 22/36
21/35
20/34
19/33
18/32
17/31
Multiply..
Probability.. 0.038306451612903
D) 14/36
13/35
12/34
11/33
X... p=0.016993464052288
Probably not correct, haven't done probability in years.
Answer:
0.6563 or 65.63% of brook trout caught will be between 12 and 18 inches
Step-by-step explanation:
Mean trout length (μ) = 14 inches
Standard deviation (σ) = 3 inches
The z-score for any given trout length 'X' is defined as:
e interval
For a length of X =12 inches:

According to a z-score table, a score of -0.6667 is equivalent to the 25.25th percentile of the distribution.
For a length of X =18 inches:

According to a z-score table, a score of 1.333 is equivalent to the 90.88th percentile of the distribution.
The proportion of trout caught between 12 and 18 inches, assuming a normal distribution, is the interval between the equivalent percentile of each length:

Hope this helps you, and good luck in the future :)
Answer:
The dimension of the sandbox is (2x+1) by (x - 3)
Step-by-step explanation:
It seems the complete question will be:
The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of x.
Step-by-step explanation:
From the question, the given expression is 2X^2-5x-3. This can be rewritten as

If the area of the sandbox in park is represented by this expression, then the dimensions of the sandbox will be the product of the factors. To determine the factors, we will factorize the given quadratic expression.
Factorizing the expression
, we get



Hence, the dimension of the sandbox is (2x+1) by (x - 3)