33/54 = 44/(a+44)
33(a+44) = 44*54
33a+ 1452 = 2376
33a = 924
a = 28
c = sqrt (33^2 + 44^2)
c = sqrt(1089 + 1936)
c = sqrt(3025)
c = 55
33/54 = 55/(b+55)
33(b+55) = 55*54
33b+ 1815 = 2970
33b = 1155
b = 35
answer
a = 28, b = 35, c = 55
Answer:
(45 - 25) / 2 × (2 + 3)
Step-by-step explanation:
Given:
45 - 25/2 × 2 + 3
By trials:
(45 - 25) / (2 × 2) + 3
= 20/4 + 3
= 20/7
Another trial:
(45 - 25)/2 × (2 + 3)
= 20/2 × 5
= 20/10
= 2
The parentheses should be inserted like this
(45 - 25) / 2 × (2 + 3)
Answer:
9 and 12
Step-by-step explanation:
The decay factor for the annual rate of change of - 55 % is 0.45.
A quantity must vary by a specific percentage each time period in order for growth or decay to be exponential.
With the function displayed to the right, you may represent exponential growth or decay.
A(x) = a( 1 + r)ˣ
Where A is the amount after x time periods, a is the initial amount, x is the number of time periods, and r is the rate of change.
Now, we have the annual rate of change as:
r = - 55 % = - 55 / 100 = - 0.55
From the function A(x) = a( 1 + r)ˣ , the corresponding factor is 1 + r.
So, let B = 1 + r
B = 1 + r
B = 1 + (- 0.55)
B = 1 - 0.55
B = 0.45
Now, the value of B is less than 1 therefore, the corresponding decay factor is 0.45.
Learn more about growth and decay factor here:
brainly.com/question/16702201
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Answer:
2 and 10
Step-by-step explanation:
6+4=10, and 6-4=2.
