72+k is equal to 180. So if you set up a equation if looks like:
72+k=180
Subtract 72 from both sides
K=108°
Your answer is 108°
Answer:
13g
Step-by-step explanation:
10g + 8g = 18g
18g - 5g = 13g
Answer: Ix - 950°C I ≤ 250°.
Step-by-step explanation:
Ok, the limits are:
700°C to 1200°C.
The first step is to find the mean these numbers:
M = (700°C + 1200°C)/2 = 950°C
Now let's find the distance between the mean and the limits (which is equal to half the difference between our numbers)
D = (1200°C - 700°C)/2 = 250°C.
Now we can write our relation as:
Ix - MI ≤ D
Ix - 950°C I ≤ 250°.
if x = 1200°C.
I1200°C - 950°CI = 250°C ≤ 250°C ---- true.
if x = 700°C
I700°C - 950°CI = I-250°CI = 250°C ≤ 250°C ---- true
| 8 | | 1 | | 6 |
-------------------
| 3 | | 5 | | 7 |
-------------------
| 4 | | 9 | | 2 |
Answer:
29.2
Step-by-step explanation:
Mean = 21.4
Standard deviation = 5.9%
The minimum score required for the scholarship which is the scores of the top 9% is calculated using the Z - Score Formula.
The Z- score formula is given as:
z = x - μ /σ
Z score ( z) is determined by checking the z score percentile of the normal distribution
In the question we are told that it is the students who scores are in the top 9%
The top 9% is determined by finding the z score of the 91st percentile on the normal distribution
z score of the 91st percentile = 1.341
Using the formula
z = x - μ /σ
Where
z = z score of the 91st percentile = 1.341
μ = mean = 21.4
σ = Standard deviation = 5.9
1.341= x - 21.4 / 5.9
Cross multiply
1.341 × 5.9 = x - 21.4
7.7526 = x -21.4
x = 7.7526 + 21.4
x = 29.1526
The 91st percentile is at the score of 29.1526.
We were asked in the question to round up to the nearest tenth.
Approximately, = 29.2
The minimum score required for the scholarship to the nearest tenth is 29.2 .
