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Drupady [299]
3 years ago
5

AssignmentSolve: 4^3x=4^2​

Mathematics
1 answer:
mart [117]3 years ago
3 0

Answer:

x =2/3

Step-by-step explanation:

4^3x=4^2​

Since the bases are the same, the exponents are the same

3x =2

Divide each side by 3

3x/3 = 2/3

x = 2/3

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Reduce 2/8 to the smallest form and 3/12 to the smallest form
iris [78.8K]

Answer:

1/4 for both

Step-by-step explanation:

2/8 -- you divide 2 by 2 you get 1, 8 divided by 2 is 4 -- 1/4

3/12 -- you divide 3 by 3 you get 1, 12 divided by 3 is 4 -- 1/4

** tip: what you do to one half of the fraction you have to do to the other

hope this helps!

4 0
3 years ago
First, she walks 4 blocks
antoniya [11.8K]

Answer:.

W. T. F.

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3 years ago
Mario is constructing a frame for a 10 in .by 8 in. photo. He wants the frame to be the same width all the way around and the to
alexgriva [62]
(10+2x)(8+2x) = 120
4x^2 + 36x + 80 = 120
x^2 + 9x + 20 = 30

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8 0
3 years ago
Read 2 more answers
19.
vichka [17]

Answer:

168

Step-by-step explanation:

Sum the parts of the ratio, 6 + 7 = 13 parts

Divide the total number of students by 13 to find the value of one part of the ratio.

364 ÷ 13 = 28 ← value of 1 part of the ratio, thus

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3 0
3 years ago
The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}


P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67

Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

5 0
3 years ago
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