Answer:
<u><em>4 : </em></u> Coordinate of Q = 
<em><u>5 : </u></em> Coordinate of point A = (-2,-2)
Explanation :
4) Given the points M(-3, -4) and T(5,0)
x₁= -3, y₁ = -4 and
x₂ = 5, y₂ = 0
m = 2, n = 1
Now apply the section formula,
{(mx₂+nx₁)/(m+n) , (my₂+ny₁)/(m+n)}
Coordinate of point Q =
5) AB:BC = 3:4
A = (x,y), end point
B = (4, 1)
C = (12, 5) end point
So, m = 3 & n = 4
x₁ = x , y₁ = y , x₂=12 & y₂ = 5
Apply section formula we get
4 = (36+4x)/7 & 1 = (15 + 4y)/7
28= 36 + 4x 7 = 4y + 15
4x =-8 4y =-8
x = -2 y = -2
Answer:
6.
Step-by-step explanation:
x/7 - 3/8 = 27/56
Multiply through by 56 , as 7 * 8 = 56 we have:
8x - 3*7 = 27
8x = 27 + 21 = 48
x = 6.
Answer:
24.0 square feet
Step-by-step explanation:
The area of the sector is given by ...
A = (1/2)r²θ . . . . . where θ is the angle in radians
The area of the circle is the same, with θ=2π, so is ...
A = πr²
__
In this problem, the area of the sector is ...
A = (1/2)(9 ft)²(24π/180) = 27π/5 ft² ≈ 16.9646 ft²
The area of the circle is ...
A = π(1.5 ft)² = 9π/4 ft² ≈ 7.0686 ft²
Then the total area of the exclamation point is ...
16.9646 +7.0686 ≈ 24.0 . . . ft²
The area is about 24.0 square feet.
Answer:
3/1
Step-by-step explanation:
All unit rates have a denominator of 1.
