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Nikolay [14]
3 years ago
8

Find the equation in standard form of the line passing through the points 3,-4 and 5,1

Mathematics
1 answer:
aliina [53]3 years ago
7 0

Answer:

5x - 2y - 23 = 0

Step-by-step explanation:

Line is passing through the points (3,\:-4)= (x_1, \:y_1) \: \&\: (5,\: 1)= (x_2,\:y_2)

Equation of line in two point form is given as:

\frac{y -y_1 }{y_1 -y_2 }  =  \frac{x -x_1 }{x_1 -x_2 } \\  \\  \therefore \:  \frac{y -( - 4) }{ - 4 -1}  =  \frac{x -3 }{3 -5 } \\  \\  \therefore \:\frac{y  +  4 }{ - 5}  =  \frac{x -3 }{ - 2 } \\  \\  \therefore \: \frac{y  +  4 }{  5}  =  \frac{x -3 }{  2 } \\  \\  \therefore \:  2(y + 4) = 5(x - 3) \\ \therefore \:  2y + 8 = 5x - 15 \\ \therefore \: 5x - 15 - 2y - 8 = 0 \\  \red{ \boxed{ \bold{\therefore \: 5x - 2y - 23 = 0}}} \\ is \: the \: required \: equation \: of \: line \: in \:  \\ standard \: form.

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