R=16
J=32
20+40(which is 20×2)=60
20-4=16
16×2=32
The range of the function is the set of all possible outputs, that is, the set of all values obtained by applying the function to elements of the domain. So the set of all values which can be obtained by applying h(x) to an element of its domain is {−4,0,5,60} , and thus that is the range of h(x) .
At least we're both struggling with the same type of math ; -;
The second one because it passes through the origin
