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2 years ago

PLEASE HELP

Mathematics

2 answers:

arsen [322]2 years ago

5 0

I think it is D. not sure tho

Umnica [9.8K]2 years ago

4 0

Just took the test. Yes, displacement is 45 meters, elapsed time is three seconds, and the direction is toward the goal.

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Please help me with this, its confusing

ser-zykov [4K]

I can’t even read it ...
step by step explanation:

3 0

3 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

How do I do this problem?

anyanavicka [17]

That's D. n² ÷ 5 because it says the division of n squared and 5.

7 0

3 years ago

Please someone help me out

Aneli [31]

Answer: maximum height of the football = 176 feet

Step-by-step explanation:

We want to determine the maximum height of the football from the ground. From the function given,

h(t) = -16t^2+96t +32, it is a quadratic function. Plotting graph if h will result to a parabolic shape. The maximum height of the football = the vertex of the parabola. This vertex is located at time, t

t = -b/2a

b = 96 and a= -16

t = -b/2a = -96/2×-16= 3

Substituting t = 3 into the function if h

h(t) = -16×3^2+96×3 +32

=-16×9 + 96×3 +32

= -144+ 288+32

=176 feet

6 0

3 years ago

$500 principle earning 4% compounded quarterly after 6 yrs

Cerrena [4.2K]

Answer:

The amount of interest earned would be $134.87 for a total of $634.87 after 6 years.

5 0

3 years ago

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