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A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms
Balls height 
To find all values of t for which the ball's height is 3 meters
We plug in 3 for h and solve for t


Solve for t


Solve using quadratic formula


After simplifying this,
= 0.11898
= 1.68102
the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec
2= f/8
Mutiply both sides by 8
(2/(8)= 16
f/8(8)= f ( crossed out 8 and 8)
Answer: f= 16
4mins---->12 cars
6mins---->(6*12/4)=18
4mins---->12
5mins---->(5*12/4)=15
And so on
Step-by-step explanation:
Putting values of x and y
2 = 4 + 2
2 = 6
= 6-2
= 4