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garik1379 [7]
4 years ago
11

Can someone help me please???!!

Mathematics
2 answers:
Mademuasel [1]4 years ago
7 0
The answer is A because your moving 5 units down which is basically -5
Vlada [557]4 years ago
4 0

Answer:

A

Step-by-step explanation:

When you shift down by 5 units, you are basically -5ing to every value in the bottom part of the chart.

For the bottom of the chart, I get:

0,2,8,14

While the top is

1,2,3,4 as nothing changes here.

The only chart like this is A.

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Jack and Jane are married and both work. However, due to their responsibilities at home, they have decided that they do not want
Zanzabum
To solve a system of inequalities we graph both of them.
The inequality representing their combined pay would be
12.50x+10.00y \geq 750.  This is because Jane makes 12.50/hr, Jack makes 10.00/hr, and they want to make at least, so greater than or equal to, $750 combined.
The inequality representing their combined hours working would be
x+y \leq 65, since they do not want their combined hours to be over 65.  In both of these inequalities, <em>x</em> represents the number of hours Jane works and <em>y</em> represent the number of hours Jack works.
To graph these, we solve both of them for <em>y</em>:
x+y \leq 65&#10;\\ x+y-x \leq 65-x&#10;\\ y \leq 65-x
12.50x+10.00y \geq750&#10;\\12.50x+10.00y-12.50x \geq 750-12.50x&#10;\\10.00y \geq 750-12.50x&#10;\\ \frac{10.00y}{10.00} \geq \frac{750}{10.00} - \frac{12.50x}{10.00}&#10;\\y \geq 75-1.25x
The attached screenshot shows what the graph looks like.  Going to the point where they intersect, we see that the shaded region that satisfies both inequalities begins when Jane works 40 hours and Jack works 25.

5 0
3 years ago
How many times larger is the value 4.74 than the value 0.047 for
Dimas [21]
Its 200 /0.5<span> = 400 times </span>
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Solve for ALL values of x given the following equation. (Simplify whenever possible) *
professor190 [17]
61:
I think thats what it would be
7 0
4 years ago
Area formula for 8c by 8c using A=bh
QveST [7]

Answer:

64 c^2

Step-by-step explanation:

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3 years ago
3 balls are placed in 3 boxes at random. What is the probability that exactly 2 boxes remain empty
matrenka [14]

If 2 boxes remain empty, it means that we put all three balls in one single box.

Suppose the full box is box number 1. For each ball, we have three choices - we may put it in box number 1, 2 or 3. This means that each box has a 1/3 chance of receiving each ball.

So:

  • we choose box 1 for ball 1 - that's a 1/3 chance
  • we choose box 1 for ball 2 - that's a 1/3 chance
  • we choose box 1 for ball 3 - that's a 1/3 chance

So, the probability of putting all balls in box 1 is

\dfrac{1}{3}\times\dfrac{1}{3}\times\dfrac{1}{3} = \dfrac{1}{3^3}

But this is the probability of putting all ballx in box 1, and you can repeat this logic for box 2 and 3.

So, the probability of putting all balls in one single box is 1/27 for each box, for a total of

\dfrac{1}{27} \times 3 = \dfrac{1}{9}

5 0
3 years ago
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