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1 year ago

3x + 2y = 6 what is x and y

Mathematics

2 answers:

Elan Coil [88]1 year ago

5 0

X-intercept is 2
y-intercept is 3
work is below

uysha [10]1 year ago

4 0

Answer:

For 3x + 2y = 6 , the x-intercept is 2 and the y-intercept is 3.

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Help with volume all help is appreciated :)

Lina20 [59]

Answer:

It would be 0.41 ft^3

Step-by-step explanation:

Alright, to start, lets get the volume of the entire cinder block and the holes within it.

1.31 * 0.66 * 0.66 ---> 0.5706...

Next with the holes, they are both 0.33 wide, 0.39 long, and just as tall at 0.66 feet.

0.33 * 0.39 * 0.66 ---> 0.0849...

Since there's two of them: 0.1698...

To finish it, subtract the hole volume from the total volume;

0.5806 - 0.1698 = 0.4108

Rounds to <u>0.41 ft</u>^3

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2 years ago

Please help! A chemist has 100ml of 25% acid solution. How much of the solution does she need to drain and replace with 70% acid

ratelena [41]

Answer:

77.78

Step-by-step explanation:

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2 years ago

What is the value of cos x°?

PolarNik [594]

Answer:

We know,

$\cos(x) = \frac{b}{h} = \frac{15}{17}$

$\cos(x) = 0.88$

.....Hope this helps:)

3 0

1 year ago

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.