Question

Write an equation for the line that passes through the points (4,8) and (6,2)

Answer 1

Answer:

The equation for the line that passes through the points (4,8) and (6,2)

 is   y + 3 x  -20 = 0

Step-by-step explanation:

Here, the given points are (4,8) and (6,2)

So, the slope of the equation joining two points is $m = \frac{y_2- y_1}{x_2 - x_1} = \frac{2-8}{6-4} =\frac{-6}{2} = -3$

⇒Slope of the given line is m = -3

Now, by POINT SLOPE FORMULA:

Equation of a line is (y - y0) = m (x-x0)

Here, equation of the line with (x0, y0) = (6,2) is

y - 2 = (-3)(x - 6)

or, y -2 = -3x + 18

⇒  y+ 3x  -20 = 0

Hence, the equation for the line that passes through the points (4,8) and (6,2)  is   y+ 3x  -20 = 0