Answer:
The value of the test statistic is <em>z</em> = 3.34.
Step-by-step explanation:
The information provided is:
The test statistic is:
Thus, the value of the test statistic is <em>z</em> = 3.34.
If . he will use the wall of the garage as one side of the pen and will construct the rest of the rectangular pen from 28 yards of fencing. The maximum area that can be achieved for the dog pen is: 392 yards².
<h3>Maximum area </h3>
Let x represent the width of the fence
Let the two widths represent 2x
Let the length of one side represent 28-x
Let A represent Area
Hence,
A=x(28-x)
=-x²+28x
Using calculus or vertex = -b/2a,
x value = -28/-2
x = 14
2x = 28
So,
Maximum area= 14 ×28
Maximum area = 392 yards²
Therefore the maximum area is 392 yards².
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The question says the machine uses up m gallons of oil each hour on weekends.
This means that if the machine works for 24 hours each day, it implies that:
There are only two days on weekends i.e. Saturday and Sunday.
This means that if the amount of oil used in 1 day in the weekend is 24m, then we can say:
Saturday: oil used is 24m
Sunday: oil used is 24m
Total oil used during the weekend is:
Answer:
1/9
Step-by-step explanation:
That's bc there are 9 possible outcomes 0,1,2,3,4,5,6,7,8,
so say an out come is 4, out of 9 chances it was 4 so there is a 1/9 of getting 4
Answer:
a = 1/2 (1 ±sqrt(47))
Step-by-step explanation:
a^2-a+12=0
We will complete the square
Subtract 12 from each side
a^2-a+12-12=0-12
a^2-a=-12
The coefficient of a = -1
-Divide by 2 and then square it
(-1/2) ^2 = 1/4
Add it to each side
a^2 -a +1/4=-12 +1/4
(a-1/2)^2 = -11 3/4
(a-1/2)^2= -47/4
Take the square root of each side
sqrt((a-1/2)^2) =sqrt(-47/4)
a-1/2 = ±i sqrt(1/4) sqrt(47)
a-1/2= ±i/2 sqrt(47)
Add 1/2 to each side
a-1/2+1/2 = 1/2± i/2 sqrt(47)
a = 1/2± i/2 sqrt(47)
a = 1/2 (1 ±sqrt(47))
