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-BARSIC- [3]
2 years ago
13

I have assessment quiz please

Mathematics
1 answer:
alekssr [168]2 years ago
7 0

Answer:

A&B

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...

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The ribbon costs $0.07 per inch
6 0
3 years ago
Read 2 more answers
Solve the system using substitution.
Maru [420]

Answer:

Given: The following system:

4x + y − 2z=18          ......[1]

2x-3y+3z = 21          ......[2]

x-3y=6                      ......[3]

we can write equation [3] as;

3y = x-6                     ......[4]

Multiply by 3 in equation [1] to both sides of an equation we get,

3 \cdot(4x+y-2z)= 3\cdot 18 or

12x+3y-6z=54              ......[5]

Substituting the equation [4] in [2] and [5] we get;

2x-(x-6)+3z=21 or

2x-x+6+3z=21

Simplify:

x+3z=15            .....[6]                       [combine like terms]

12x+x-6-6z =54

Simplify:

13x-6z=60         ......[7]        [Combine like terms]

On Solving equation [6] and [7] simultaneously,

x+3z=15

13x-6z=60

we get the value of x

i.e, x=6

Substitute the value of x in equation x+3z=15  we get

6+3z=15 or

3z=9

Simplify:

z=3

Also, substitute the value of x=6 in equation [3] we get the value of y;

x-3y=6

6-3y=6 or

-3y = 0

Simplify:

y = 0

Therefore, the solution to the system of three linear equation is, (6, 0 , 3)


5 0
3 years ago
Helpppppppppppppppppp
irina [24]

Option D:

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7

Solution:

Given expression is \left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right).

<u>To find the product of the expression:</u>

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)

Multiply each term of the first term with each term of the 2nd term.

           =y^{2}\left(8 y^{2}+y+1\right) +3 y\left(8 y^{2}+y+1\right) +7\left(8 y^{2}+y+1\right)

Using the exponent rule: a^m \cdot a^n = a^{m+n}

           =\left(8 y^{4}+y^3+y^2\right) +\left(24 y^{3}+3y^2+3y\right) +\left(56 y^{2}+7y+7\right)

           =8 y^{4}+y^3+y^2+24 y^{3}+3y^2+3y+56 y^{2}+7y+7

Arrange the terms with same power.

           =8 y^{4}+y^3+24 y^{3}+y^2+3y^2+56 y^{2}+7y+3y+7

           =8 y^{4}+25 y^{3}+60 y^{2}+10y+7

Hence option D is the correct answer.

\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7

6 0
3 years ago
Help me I don’t understand what to do
tatiyna

Answer:

Step-by-step explanation:

5 0
3 years ago
16(-4/3)<br> Please help me!!!
baherus [9]
I got -64/3 for this problem.
3 0
3 years ago
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