Answer:
Let two consecutive multiples of 3 be x and (x+3)
A/q,
x * (x+3) = 648
➡ x² + 3x = 648
➡ x² + 3x -648 = 0
➡ x² + 27x - 24x -648 = 0
➡ x ( x + 27 ) -24 ( x +27)
➡ ( x - 24) ( x + 27)
➡ x = 24 and x = -27
so, we take x = 24.
Required multiples of 3
➡ x = 24
➡ x +3 = 24+3 = 27.
Answer:
B) y = -3x - 5
Hope this helps!
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<span>Let n = number
n = 32 + 8
n = 40</span>
Answer:
94
Step-by-step explanation:
multiply the averages by their weighted percentage
x = final exam
88(.2) + 84(.2) + 92(.4) + x(.2) = 90
solve for x
x(.2) = 90 - 71.2 = 18.8
divide both sides by 0.2
x = 94
Answer:
6 miles
Step-by-step explanation:
Let's set up a ratio:

We can use "cross multiplication" to solve for x
Cross multiplication is multiplying the numerator of the first fraction by the denominator of the second fraction and the denominator of the first fraction by the numerator of the second fraction.


Divide both sides by 50 to isolate x
