Answer:
4
Step-by-step explanation:
For the first triangle which is triangle <KJL
Hypotenuse= 8✓2
Angle=30°
Opposite = ?
Therefore we will use Sine formula
Sin30° = Y/8✓2
Y=4✓2
For the second triangle which is triangle <JML
Hypotenuse= 4✓2
Opposite=X
Angle=45°
Therefore we will use Sine formula again
Sin45°=X/4✓2
X=4
Answer:
y=x+1
Step-by-step explanation:
first find the slope using the two coordinates:
use the slope formula- m=y^2-y^1/x^2-x^1
6-2/5-1
=4/4
=1
y=mx+b
now plug in one of the coordinates, and the slope we just found into the slope intercept formula
2=1(1)+b
2=1+b
subtract 1 from both sides
1=b
1=b; m=1,
y=x+1
Use the z-score:
112 - 100
For 112, the z-score is --------------- = 12/15, or 0.8.
15
Next, find the AREA under the standard normal curve TO THE LEFT OF 0.8.
Use either a z-score table or a calculator for this purpose.
Using my calculator, I found that this area is 0.532. That places 112 in the 53rd percentile.
82 would be in a lower percentile: the 12th percentile.
Let me know if you have questions about how to use a calculator to do these calculations.
f(x) = 7x - 1
-2 = 7x - 1
-2 + 1 = 7x
-1 = 7x
x = -1/7
0 = 7x - 1
1 = 7x
x = 1/7
4 = 7x - 1
4 + 1 = 7x
5 = 7x
x = 5/7
8 = 7x - 1
8 + 1 = 7x
9 = 7x
x = 9/7
So the domain is
Domain = {-1/7, 1/7, 5/7, 9/7}
