The area of the following rectangle is 24 square units.

There are 576 boys and 448 girls in a school that are to be divided into equal sections of either boys or girls alone. The total

scZoUnD [109]

The total numbers of sections are 16.

Step-by-step explanation:

Given:

Number of boys in school = 576

Number of girls in school = 448

To find: Total Number of sections such that each section has either boys or girls.

Height Common Factor ( HCF ) of both number gives the number of students in a section.

HCF of 576 and 448

576 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3

448 = 2 × 2 × 2 × 2 × 2 × 2 × 7

HCF = 2 × 2 × 2 × 2 × 2 × 2 = 64

Number of sections of Boys = 576/64 = 9

Number of sections of girls 448/64 = 7

Total Number of sections = 9 + 7 = 16

Therefore, The total numbers of sections are 16.

6 0

3 years ago

A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the

juin [17]

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the commercial improved the mean purchase potential rating.

Step-by-step explanation:

If we calculate the difference in ratings we have:

After Before Difference

1 6 -5

5 2 3

6 4 2

3 7 -4

7 4 3

4 3 1

5 3 2

5 6 -1

9 8 1

7 7 0

5 8 -3

6 6 0

We will calculate the mean and standard deviation of the difference to test them later.

The sample size is n=12.

The mean is:

$M=\dfrac{1}{12}\sum_{i=1}^{12}((-5)+3+2+(-4)+3+1+2+(-1)+1+0+(-3)+0)\\\\\\ M=\dfrac{-1}{12}=-0.083$

The standard deviation is:

$s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{12}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{11}\cdot [(-5-(-0.083))^2+(3-(-0.083))^2+...+(0-(-0.083))^2]}\\\\\\$

$s=\sqrt{\dfrac{1}{11}\cdot [(24.17)+(9.51)+...+(1.17)+(0.01)+(8.51)+(0.01)]}\\\\\\s=\sqrt{\dfrac{78.92}{11}}=\sqrt{7.174}\\\\\\s=2.678$

The null hypothesis states that the mean rating "after" would be less than or equal to the mean rating "before." The alternative hypothesis states that the mean rating difference is greater than 0.

Then, the null and alternative hypothesis:

$H_0: \mu\leq0\\\\H_a:\mu> 0$

The significance level is 0.05.

The sample has a size n=12.

The sample difference is d=-0.083.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=2.678.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2.678}{\sqrt{12}}=0.773$

Then, we can calculate the t-statistic as:

$t=\dfrac{\bar d}{s/\sqrt{n}}=\dfrac{-0.083}{0.773}=-0.108$

The degrees of freedom for this sample size are:

$df=n-1=12-1=11$

This test is a right-tailed test, with 11 degrees of freedom and t=-0.108, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>-0.108)=0.542$

As the P-value is greater than the significance level, the effect is not significant. The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the commercial improved the mean purchase potential rating.

5 0

3 years ago

9. Raymond and Rose were working with exponents. Part A: Raymond claims that 5^5 * 5^2 = 5^3. Rose argues that 5^5 * 5^2 = 5^7.

tamaranim1 [39]

Answer: Rose is correct 5^5*5^2=5^7

Step-by-step explanation:

when multiplying two powers that have the same base you can add the exponent s (product property’s)

6 0

3 years ago

Three partners, Luc, Deborah and Melanie, share the profits of a bussiness in the ratio 2:3:7 respectively. The profit for this

valentina_108 [34]

Add all parts shared 2+3+7=12

Therefore 1 part is 176,496÷12= $14,708.

This means:
Luc has 2 parts: $14,708×2=$29,416
Deborah has 3 parts: $14,708×3=$44,124
Melanie has 7 parts: $14,708×7=$102,956

To check add all values together. If it makes the total amount, then the share is correct. 29,416+44,124+102,956=$176,496

8 0

3 years ago

Read 2 more answers

Help plssssssssssssssssssssssssssssssssss

LenaWriter [7]

Answer:

The answer to this question is B

Step-by-step explanation:

5 0

3 years ago