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Volgvan
3 years ago
10

Eli sells refrigerators. His base salary is $250 per week, and his commission is $50 for each refrigerator (r) that he sells. He

needs to make more than $900 this week. Which TWO statements are correct for this situation?
A) $50r + $250 < $900
B) $50r ≥ $900
C) $50r + $250 > $900
D) Eli needs to sell more than 13 refrigerators.
E) Eli needs to sell more than 15 refrigerators.
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

C and e

Step-by-step explanation:

the 50r represents the commision he receives for each refrigerator he sells, and the 250 is the base salary and it’s bigger than, >, because he needs to earn MORE than 900 and you get D by solving the inequality,  50r >900, r>15

would be amazing if you marked this brainliest :)

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What value of c makes the trinomial below a perfect square x2 + 7x + c?
Daniel [21]
We have that
x²<span> + 7x + c
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<span>Complete the square. Remember to balance the equation 
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Rewrite as perfect squares

(x+3.5)²+ c-3.5²
so
c-3.5² must be zero
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the answer is
the value of c must be 12.25

5 0
3 years ago
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Marcus painted 1/3 of his bedroom in 4/5 of an hour. At this rate, how long would it take him the paint the entire room? I need
expeople1 [14]
So it took him 4/5 of an  hour to paint 1/3 
that means there is still 2/3 to go 
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<u>4/5</u>    = <u> ? </u>
1/3       2/3 

using cross multiplication

(4/5)(2/3) = (1/3) (?)
8/15 = 1/3 ?
divide both sides by 1/3
so that will be 8/5
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2 years ago
Which expressions are equivalent to 2(2x + 4y + x − 2y)?
joja [24]

Answer: 2(3x + 2y) and 6x + 4y

Step-by-step explanation:

Hi, to answer this question we have to solve the expression.

2(2x + 4y + x − 2y)

First we have to simplify the expression within the brackets.

2 (2x + x +4y -2y)

  • 2( 3x + 2y)

We have the first equivalent expression. Now to obtain the second expression we apply distributive property:

2 (3x) + 2 ( 2y)

  • 6x + 4y

In conclusion 2(3x + 2y) and 6x + 4y are equivalent expressions to 2(2x + 4y + x − 2y).

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3 years ago
What is the equation of the line passing through the points (2, 6) and (-2, 4)
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2 years ago
The diagram shows a regular octagon ABCDEFGH. Each side of the octagon has length 10cm. Find the area of the shaded region ACDEH
Zolol [24]

The area of the shaded region /ACDEH/ is 325.64cm²

Step 1 - Collect all the facts

First, let's examine all that we know.

  1. We know that the octagon is regular which means all sides are equal.
  2. since all sides are equal, then all sides are equal 10cm.
  3. if all sides are equal then all angles within it are equal.
  4. since the total angle in an octagon is 1080°, the sum of each angle within the octagon is 135°.

Please note that the shaded region comprises a rectangle /ADEH/ and a scalene triangle /ACD/.

So to get the area of the entire region, we have to solve for the area of the Scalene Triangle /ACD/ and add that to the area of the rectangle /ADEH/

Step 2 - Solving for /ACD/

The formula for the area of a Scalene Triangle is given as:

A = \sqrt{S(S-a)(S-b)(S-c) square units}

This formula assumes that we have all the sides. But we don't yet.

However, we know the side /CD/ is 10cm. Recall that side /CD/ is one of the sides of the octagon ABCDEFGH.

This is not enough. To get sides /AC/ and /AD/ of Δ ACD, we have to turn to another triangle - Triangle ABC. Fortunately, ΔABC is an Isosceles triangle.

Step 3 - Solving for side AC.

Since all the angles in the octagon are equal, ∠ABC = 135°.

Recall that the total angle in a triangle is 180°. Since Δ ABC is an Isosceles triangle, sides /AB/ and /BC/ are equal.  

Recall that the Base angles of an isosceles triangle is always equal. That is ∠BCA and ∠BAC are equal. To get that we say:

180° - 135° = 45° [This is the sum total of ∠BCA and ∠BAC. Each angle therefore equals

45°/2 = 22.5°

Now that we know all the angles of Δ ABC and two sides /AB/ and /BC/, let's try to solve for /AC/ which is one of the sides of Δ ACD.

According to the Sine rule,

\frac{Sin 135}{/AC/} = \frac{Sin 22.5}{/AB/} = \frac{Sin 22.5}{/BC/}

Since we know side /BC/, let's go with the first two parts of the equation.

That gives us \frac{0.7071}{/AC/}  = \frac{0.3827}{10}

Cross multiplying the above, we get

/AC/ = \frac{7.0711}{0.3827}

Side /AC/ = 18.48cm.

Returning to our Scalene Triangle, we now have /AC/ and /CD/.

To get /AD/ we can also use the Sine rule since we can now derive the angles in Δ ABC.

From the Octagon the total angle inside /HAB/ is 135°. We know that ∠HAB comprises  ∠CAB which is 22.5°, ∠HAD which is 90°. Therefore, ∠DAC = 135° - (22.5+90)

∠DAC = 22.5°

Using the same deductive principle, we can obtain all the other angles within Δ ACD, with ∠CDA = 45° and ∠112.5°.

Now that we have two sides of ΔACD and all its angles, let's solve for side /AD/ using the Sine rule.

\frac{Sin 112.5}{/AD/} = \frac{Sin 45}{18.48}

Cross multiplying we have:

/AD/ = \frac{17.0733}{0.7071}

Therefore, /AD/ = 24.15cm.

Step 4 - Solving for Area of ΔACD

Now that we have all the sides of ΔACD, let's solve for its area.

Recall that the area of a Scalene Triangle using Heron's formula is given as

A = \sqrt{S(S-a)(S-b)(S-c) square units}

Where S is the semi-perimeter given as

S= (/AC/ + /CD/ + /DA/)/2

We are using this formula because we don't have the height for ΔACD but we have all the sides.

Step 5 - Solving for Semi Perimeter

S = (18.48 + 10 + 24.15)/2

S = 26.32

Therefore, Area =  \sqrt{26.32(26.32-18.48)(26.32-10)(26.32-24.15)}

A = \sqrt{26.32 * 7.84*16.32 * 2.17)}

A = \sqrt{7,307.72} Square cm.

A of ΔACD = 85.49cm²

Recall that the shape consists of the rectangle /ADEH/.

The A of a rectangle is L x B

A of /ADEH/ = 240.15cm²


Step 6 - Solving for total Area of the shaded region of the Octagon

The total area of the Shaded region /ACDEH/, therefore, is 240.15 + 85.49

= 325.64cm²


See the link below for more about Octagons:
brainly.com/question/4515567

8 0
2 years ago
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