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Volgvan
3 years ago
10

Eli sells refrigerators. His base salary is $250 per week, and his commission is $50 for each refrigerator (r) that he sells. He

needs to make more than $900 this week. Which TWO statements are correct for this situation?
A) $50r + $250 < $900
B) $50r ≥ $900
C) $50r + $250 > $900
D) Eli needs to sell more than 13 refrigerators.
E) Eli needs to sell more than 15 refrigerators.
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

C and e

Step-by-step explanation:

the 50r represents the commision he receives for each refrigerator he sells, and the 250 is the base salary and it’s bigger than, >, because he needs to earn MORE than 900 and you get D by solving the inequality,  50r >900, r>15

would be amazing if you marked this brainliest :)

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Mon Tue Wed Thur Fri Sat Sun –2 –6 –3 2 6 –7 0 a. Arrange the temperatures in order from coldest to warmest. b. On a day in Janu
zvonat [6]

Answer:

A.) -7, -6, -3, -2, 0, 2, 6

B.) Jacob is correct, the larger the negative number, the lower the number is. So, since -11 is smaller than -7, it will be colder.

C.) Minneapolis is colder since -41 is way lower than -15.

-41<-15

7 0
3 years ago
Solve the following System of Three Equations:<br> x−3y+z=−15<br> 2x+y−z=−2<br> x+y+2z=1
SashulF [63]

Answer:

x = -3 , y = 4 , z = 0

Step-by-step explanation:

Solve the following system:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for z:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Solve for z.

Subtract x - 3 y from both sides:

{z = 3 y + (-x - 15)

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Perform a substitution.

Substitute z = -15 - x + 3 y into the second and third equations:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

x + y + 2 (-15 - x + 3 y) = 1

Hint: | Expand the left hand side of the equation x + y + 2 (-15 - x + 3 y) = 1.

x + y + 2 (-15 - x + 3 y) = x + y + (-30 - 2 x + 6 y) = -30 - x + 7 y:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Isolate terms with x to the left hand side.

Subtract 15 - 2 y from both sides:

{z = -15 - x + 3 y

3 x = 2 y - 17

-30 - x + 7 y = 1

Hint: | Solve for x.

Divide both sides by 3:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

-30 - x + 7 y = 1

Hint: | Perform a substitution.

Substitute x = (2 y)/3 - 17/3 into the third equation:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Choose an equation and a variable to solve for.

In the third equation, look to solve for y:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Isolate terms with y to the left hand side.

Add 73/3 to both sides:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 = 76/3

Hint: | Solve for y.

Multiply both sides by 3/19:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

y = 4

Hint: | Perform a back substitution.

Substitute y = 4 into the first and second equations:

{z = -x - 3

x = -3

y = 4

Hint: | Perform a back substitution.

Substitute x = -3 into the first equation:

{z = 0

x = -3

y = 4

Hint: | Sort results.

Collect results in alphabetical order:

Answer:  {x = -3 , y = 4 , z = 0

4 0
3 years ago
What point in the feasible region maximizes the objective function, 3x + y ≤ 12, x+y ≤5, x ≥0,y ≥0
forsale [732]

Step-by-step explanation:

We have to find the point in the feasible region which maximizes the objective function. To find that point first we need to graph the given inequalities to find the feasible region.

Steps to graph 3x + y ≤ 12:

First we graph 3x + y = 12 then shade the graph for ≤.

plug any value of x say x=0 and x=2 into 3x + y = 12 to find points.

plug x=0

3x + y = 12

3(0) + y = 12

0 + y = 12

y = 12

Hence first point is (0,12)

Similarly plugging x=2 will give y=6

Hence second point is (2,6)

Now graph both points and joint them by a straight line.

test for shading.

plug any test point which is not on the graph of line like (0,0) into original inequality 3x + y ≤ 12:

3(0) + (0) ≤ 12

0 + 0 ≤ 12

0 ≤ 12

Which is true so shading will be in the direction of test point (0,0)


We can repeat same procedure to graph other inequalities.

From graph we see that ABCD is feasible region whose corner points will result into maximum or  minimu for objective function.

Since objective function is not given in the question so i will explain the process.

To find the maximum value of objective function we plug each corner point of feasible region into objective function. Whichever point gives maximum value will be the answer

7 0
3 years ago
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bazaltina [42]

Answer:

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Step-by-step explanation:

The equation of the line would have a slope of 2, since parallel lines have the same slope. We can use that and the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y + 2 = 2(x - 3)

y + 2 = 2x - 6

y = 2x - 8

7 0
3 years ago
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Scrat [10]
Use T and J as names.

T=2x
J=3T  but T=2x, so
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J=6x
3 0
3 years ago
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