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nydimaria [60]
3 years ago
5

Which statement best describes the electronegativity of an element?

Chemistry
2 answers:
iragen [17]3 years ago
7 0

<u>Answer:</u> The correct answer is Option E.

<u>Explanation:</u>

Electronegativity is the chemical property of an element. This is defined as the tendency of an atom to attract the shared pair of electrons towards itself when a bond is formed.

This property of an atom increases as we move from left to right in a period because the number of charge on the nucleus increases.

But this property decreases as we move from top to bottom in a group because electrons get added up in the new shells which make it further far away from the nucleus.

Thus, the correct answer is Option E.

faust18 [17]3 years ago
6 0
“Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons.”

https://www.chemguide.co.uk/atoms/bonding/electroneg.html
^this link may help you understand. Good luck!
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An iron nail with a mass of 12 g absorbs 12 J of heat.
Fynjy0 [20]

Answer:

27.25°C

Explanation:

hello,

this question involves heat transfer in an object and to find the final temperature, we'll use formula for heat transfer

data;

mass = 12g

heat energy (Q) = 12J

initial temperature (T1) = 25°C

final temperature (T2) = x

specific heat capacity (c) = 0.444J/g°C

heat energy(Q) = mcΔt

Q = mc(T2 - T1)

12 = 12*0.444*(x - 25)\\12 = 5.328x - 133.2\\collect like terms\\12 + 133.2 = 5.328x\\145.2 = 5.328x\\divide both sides by 5.328 and solve for x\\x = 145/5.328\\x = 27.25C\\

the final temperature was 27.25°C

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3 years ago
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kotegsom [21]
It's density is 1g/cm3
8 0
4 years ago
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geniusboy [140]

Answer:

No

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5 0
3 years ago
A major component of gasoline is octane, C8H18. When octane is burned in air, it chemically reacts with oxygen gas (O2) to produ
ddd [48]

Answer:

m_{CO_2}=2.8gCO_2

Explanation:

Hello,

In this case, the combustion of octane is chemically expressed by:

C_8H_{18}+\frac{25}{2} O_2\rightarrow 8CO_2+9H_2O

In such a way, due to the 25/2:8 molar ratio between oxygen and carbon dioxide, we can compute the yielded grams of carbon dioxide (molar mass 44 g/mol) as shown below:

m_{CO_2}=3.2gO_2*\frac{1molO_2}{32gO_2} *\frac{8molCO_2}{\frac{25}{2}molO_2 } *\frac{44gCO_2}{1molCO_2}\\ \\m_{CO_2}=2.8gCO_2

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4 years ago
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