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tensa zangetsu [6.8K]
3 years ago
5

An iron nail with a mass of 12 g absorbs 12 J of heat.

Chemistry
1 answer:
Fynjy0 [20]3 years ago
6 0

Answer:

27.25°C

Explanation:

hello,

this question involves heat transfer in an object and to find the final temperature, we'll use formula for heat transfer

data;

mass = 12g

heat energy (Q) = 12J

initial temperature (T1) = 25°C

final temperature (T2) = x

specific heat capacity (c) = 0.444J/g°C

heat energy(Q) = mcΔt

Q = mc(T2 - T1)

12 = 12*0.444*(x - 25)\\12 = 5.328x - 133.2\\collect like terms\\12 + 133.2 = 5.328x\\145.2 = 5.328x\\divide both sides by 5.328 and solve for x\\x = 145/5.328\\x = 27.25C\\

the final temperature was 27.25°C

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Bath salts are typically composed of the ingredients listed below. Identify each item as being acidic, basic, or neutral when di
Gwar [14]

Answer:

NaCl neutral

Na₂SO₄ basic

NaHCO₃ basic

K₃PO₄ basic

Na₃C₆H₅O₇ basic

CaCl₂ neutral

Sodium oxalate (Na₂C₂O₄) dissolves and dissociates in water.

Oxalic acid (C₂H₂O₄) dissolves and dissociates in water

Explanation:

<em>Identify each item as being acidic, basic, or neutral when dissolved in water. If a particular ingredient does make an acidic or basic solution, describe how this occurs.</em>

<em />

NaCl

When NaCl is dissolved in water the resulting solution is neutral.

Na₂SO₄

When Na₂SO₄ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the SO₄²⁻ ion.

SO₄²⁻(aq) + H₂O(l) ⇄ HSO₄⁻(aq) + OH⁻(aq)

NaHCO₃

When NaHCO₃ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the HCO₃⁻ ion.

HCO₃⁻(aq) + H₂O(l) ⇄ H₂CO₃(aq) + OH⁻(aq)

K₃PO₄

When K₃PO₄ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the PO₄³⁻ ion.

PO₄³⁻(aq) + H₂O(l) ⇄ HPO₄²⁻(aq) + OH⁻(aq)

Na₃C₆H₅O₇ (sodium citrate)

When Na₃C₆H₅O₇ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the C₆H₅O₇³⁻ ion.

C₆H₅O₇³⁻(aq) + H₂O(l) ⇄ C₆H₆O₇²⁻(aq) + OH⁻(aq)

CaCl₂

When CaCl₂ is dissolved in water the resulting solution is neutral.

Sodium oxalate (Na₂C₂O₄) dissolves and dissociates in water according to the following equation:

Na₂C₂O₄(aq) ⇄ 2 Na⁺(aq) + C₂O₄²⁻(aq)

Oxalic acid (C₂H₂O₄) dissolves and dissociates in water according to the following equation:

C₂H₂O₄(aq) ⇄ C₂HO₄⁻(aq) + H⁺(aq)

4 0
3 years ago
Can anyone solve this?
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3 years ago
Can someone please help me with this?
yaroslaw [1]

Answer:

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3 0
3 years ago
Read 2 more answers
This is my chemistry worksheet. It's a new topic my teacher will barely review with us. Help please???
TEA [102]
So to balance an equation, you need to get the same amount of each type of element on either side of the --> . So you pretty much are given the subscripts in the equations and you need to add coefficients (just normal numbers) in front of any formula that needs it, keeping anything balance.
KCl_{3}  + O_{2}  -\ \textgreater \  KCl_{3}
turns into
2KCl_{3}+ 3O_{2} -> 2KCl_{3}

These coefficient numbers are the molar ratios, so 2 moles of KCl3 for every 3 moles of O2   so 1. 3:2

Then you can use these ratios of find out how many moles of one thing are needed if you are given the amount of another.
\frac{moles of element 1}{cofficient 1}  =  \frac{moles of element 2}{cofficient 2}
and use cross multiplication to solve for whatever you don't know


<span />
6 0
3 years ago
A sample of 10.6 g of KNO3 was dissolved in 251.0 g of water at 25 oC in a calorimeter. The final temperature of the solution wa
finlep [7]

Answer:

36.55kJ/mol

Explanation:

The heat of solution is the change in heat when the KNO3 dissolves in water:

KNO3(aq) → K+(aq) + NO3-(aq)

As the temperature decreases, the reaction is endothermic and the molar heat of solution is positive.

To solve the molar heat we need to find the moles of KNO3 dissolved and the change in heat as follows:

<em>Moles KNO3 -Molar mass: 101.1032g/mol-</em>

10.6g * (1mol/101.1032g) = 0.1048 moles KNO3

<em>Change in heat:</em>

q = m*S*ΔT

<em>Where q is heat in J,</em>

<em>m is the mass of the solution: 10.6g + 251.0g = 261.6g</em>

S is specififc heat of solution: 4.184J/g°C -Assuming is the same than pure water-

And ΔT is change in temperature: 25°C - 21.5°C = 3.5°C

q = 261.6g*4.184J/g°C*3.5°C

q = 3830.87J

<em>Molar heat of solution:</em>

3830.87J/0.1048 moles KNO3 =

36554J/mol =

<h3>36.55kJ/mol</h3>

<em />

6 0
3 years ago
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