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andreyandreev [35.5K]
3 years ago
15

Are alternate interior angles supplementary?

Mathematics
1 answer:
Naily [24]3 years ago
8 0

Answer:

No.

Step-by-step explanation:

Alternate interior angles are congruent.

_____

<em>More about such angles</em>

Alternate exterior angles are congruent.

Same-side interior angles are supplementary.

Same-side exterior angles are supplementary.

Linear angles are supplementary.

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What is the area of the triangle?<br> 16<br> 8<br> 10
sertanlavr [38]

Answer:

64

Step-by-step explanation:

Find the area of both triangles inside the bigger triangle and add them together.

Use the Pythagorean theorem to find the missing length of the leg in the smallest triangle:

a² + b² = c²

8² + b² = 10²

64 + b² = 100

36 = b²

6 = b

Calculate the area of the smaller triangle:

1/2(<em>b</em>x<em>h</em>)

1/2(6 x 8)

1/2(48)

24

Calculate the area of the bigger triangle:

<em>We know that the longer leg is 10 units because we were able to subtract the length of the smaller triangle's leg from 16.</em>

1/2(<em>b</em>x<em>h</em>)

1/2(10 x 8)

1/2(80)

40

Add both areas to find the area of the largest triangle:

40 + 24 = 64

3 0
3 years ago
What is the sign of a^72*(-3/7) when a is a negative number
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Answer:

Sign is positive

Step-by-step explanation:

Negative number^72=negative number

negative number *(-3/7)=posigive number

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3 years ago
Does the rule y =(4)(x) represent a linear or exponential function?
lana66690 [7]

The rule is exponential function.

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Marty drew a model of the school library, the total area of the floor is 132 square centimeters, What is the area of the shaded
dlinn [17]

Answer:

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the answer for this problem?
Y_Kistochka [10]
This is a problem involving the subtraction of two functions f(x) and g(x):

<span>if f(x)=3x-1 and g(x)=x+2, find (f-g)(x).  In other words, find:

</span><span>  f(x)  = 3x-1 
-{g(x) -(x+2)
-----------------
f(x) - g(x) = 3x - 1 - x - 2 = 2x - 3  (answer)</span>
4 0
3 years ago
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