Answer:
B) (3, –2)
Explanation:
The inequality is y ≤ –x + 1
There are two ways to do this. You can try the four options by seeing where they lie on the graph, or by inputting them into the inequality and seeing if they check out. I am going to do a bit of both.
I know that the solution cannot have two positive coordinates because the first quadrant is not part of the solution, so I won't guess A or C.
I'll try (3, –2) (which is option B).
On the graph, (3, –2) is on the line, which means it is part of the solution because the line is solid and the inequality is a greater than or equal to sign.
Try it in the inequality:
y ≤ –x + 1
–2 ≤ –3 + 1
–2 ≤ –2 yes this checks out.
Algebraic expression: 100 = 25 + n
Answer: n = 75
Answer:
Option (1)
Step-by-step explanation:
Two functions 'f' and 'g' have been graphed in the picture attached.
Both the functions will be equal at the points where the values of these functions are equal.
Those points are the point of intersection of both the functions on the given graph.
At x = -4,
f(-4) = g(-4) = 4
At x = 0,
f(0) = g(0) = 4
Therefore, Option (1) will be the answer.
Answer:
0.0786
Step-by-step explanation:
It is given that Bartholemew had drawn the replacement of 160 tickets.
There are five tickets = [0, 0, 0, 1, 2]
Now we need to find the estimate of the ticket that has 1 on it and it turns up on the 32 draws exactly.
Since the probability of the drawing 1 out of 5 tickets is given by, 
So the binomial with the parameter of n = 160 and p = 0.2, we get
P (it turns up on exactly 32 draws) = P(X = 32)
Therefore,
= 0.0786
Answer:
a. h = 60t − 4.9t²
b. 12.2 seconds
c. 183.7 meters
Step-by-step explanation:
a. Given:
y₀ = 0 m
v₀ = 60 m/s
a = -9.8 m/s²
y = y₀ + v₀ t + ½ at²
h = 0 m + (60 m/s) t + ½ (-9.8 m/s²) t²
h = 60t − 4.9t²
b. When the ball lands, h = 0.
0 = 60t − 4.9t²
0 = t (60 − 4.9t)
t = 0 or 12.2
The ball lands after 12.2 seconds.
c. The maximum height is at the vertex of the parabola.
t = -b / (2a)
t = -60 / (2 × -4.9)
t = 6.1 seconds
Alternatively, the maximum height is reached at half the time it takes to land.
t = 12.2 / 2
t = 6.1 seconds
After 6.1 seconds, the height reached is:
h = 60 (6.1) − 4.9 (6.1)²
h = 183.7 meters
