Answer:
You cannot solve for x on any of these. it will just be the same answer.
Step-by-step explanation:
36 cm^2
Step-by-step explanation:
<u>Small</u><u> </u><u>window</u>
Length: 2cm
Width: 2cm
<u>Area</u><u>:</u> 4 cm^2
<u>Big window</u>
Length: 4cm
Width: 3cm
<u>Area</u><u>:</u> 12 cm^2
Total area of the windows:
(Area of 4 small windows + area of 1 big window)
(4 cm^2 x 4 + 12cm^2)
= <u>28 cm^2</u>
<u>Above</u><u> </u><u>window</u><u> </u><u>(</u><u>approx</u><u>.</u><u>)</u>
<u>Rectangle</u>
Length: 3cm
Width: 2cm
<u>Area</u><u>:</u> 6 cm^2
<u>T</u><u>riangle</u>
Base: 1cm
Height: 1cm
<u>Area</u><u>:</u> 2 x 0.5 cm^2 = 1 cm^2
<u>Square</u><u> </u><u>(</u><u>between</u><u> </u><u>the</u><u> </u><u>triangles</u><u>)</u>
Length: 1cm
Width: 1cm
<u>Area</u><u>:</u> 1 cm^2
= 8 cm^2
<u>TOTAL</u><u> </u><u>AREA</u><u> </u><u>OF</u><u> </u><u>ALL</u><u> </u><u>WINDOWS</u>
= AREA OF 4 WINDOWS + AREA OF BIG WINDOW + AREA OF ABOVE WINDOW
= 16 cm^2 + 12 cm^2 + 8 cm^2
<h3>
= <u>
36 cm^2</u></h3>
<em>I</em><em> </em><em>hope</em><em> </em><em>I</em><em> </em><em>made</em><em> </em><em>the</em><em> </em><em>explanations</em><em> </em><em>clear</em><em> </em><em>enough</em><em> </em><em>to</em><em> </em><em>make</em><em> </em><em>it</em><em> </em><em>easier</em><em> </em><em>for</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>understand</em><em>!</em>
To simplify
![\sqrt[4]{\dfrac{24x^6y}{128x^4y^5}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cdfrac%7B24x%5E6y%7D%7B128x%5E4y%5E5%7D%7D)
we need to use the fact that
![\sqrt[4]{x^4}=|x|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E4%7D%3D%7Cx%7C)
Why the absolute value? It's because
.
We start by rewriting as
![\sqrt[4]{\dfrac{2^23x^6y}{2^6x^4y^5}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cdfrac%7B2%5E23x%5E6y%7D%7B2%5E6x%5E4y%5E5%7D%7D)
![\sqrt[4]{\dfrac{2^23x^4x^2y}{2^42^2x^4y^4y}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cdfrac%7B2%5E23x%5E4x%5E2y%7D%7B2%5E42%5E2x%5E4y%5E4y%7D%7D)
Since
, we have
, and the above reduces to
![\sqrt[4]{\dfrac{3x^2y}{2^4y^4y}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cdfrac%7B3x%5E2y%7D%7B2%5E4y%5E4y%7D%7D)
Then we pull out any 4th powers under the radical, and simplify everything we can:
![\dfrac1{\sqrt[4]{2^4y^4}}\sqrt[4]{\dfrac{3x^2y}{y}}](https://tex.z-dn.net/?f=%5Cdfrac1%7B%5Csqrt%5B4%5D%7B2%5E4y%5E4%7D%7D%5Csqrt%5B4%5D%7B%5Cdfrac%7B3x%5E2y%7D%7By%7D%7D)
![\dfrac1{|2y|}\sqrt[4]{3x^2}](https://tex.z-dn.net/?f=%5Cdfrac1%7B%7C2y%7C%7D%5Csqrt%5B4%5D%7B3x%5E2%7D)
where
allows us to write
, and this also means that
. So we end up with
![\dfrac{\sqrt[4]{3x^2}}{2y}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%7D%7B2y%7D)
making the last option the correct answer.
Answer:
z= 13
x= 36
y= 18
Step-by-step explanation:
Solving for z.
We know that 108 degrees and (8z+4) are alternate exterior angles, so they are equal to each other.
We can set both of those angles equal to each other, and solve for our missing side, z.
108= 8z+4
104=8z
z= 13
Solving for x.
We know that 108 degrees and (3x) are alternate interior angles, so they would equal each other.
We can set both of these angles equal to each other, and solve for our missing side, x.
3x=108
x= 36
Solve for y.
We know that (4y) and (3x) are same side interior angles, so they would make 180 degrees. We know that (3x) would equal 108.
4y+108=180
4y= 72
y= 18