Answer:
The equation of line passing through points (1 , 0) is x - 5 y - 1 = 0
Step-by-step explanation:
Given equation of line as
x + 5 y = 30
Now, equation of line in standard form is y = m x + c
where m is the slope
So, x + 5 y = 30
Or, 5 y = - x + 30
Or, y = - x + 6
So, Slope of this line m = -
Again , let the slope of other line passing through point (1 , 0) is M
And Both lines are perpendicular , So , products of line = - 1
i.e m × M = - 1
Or, M = -
Or, M = - 1 × - =
So, equation of line with slope M and points (1, 0) is
y - = M × (x - )
Or, y - ( 0 ) = × ( x - 1 )
Or, y = x - × 1
Or, y = x -
or, y + = x
Or, 5×y + 1 = x
∴ 5 y + 1 = x
I.e x - 5 y - 1 = 0
Hence The equation of line passing through points (1 , 0) is x - 5 y - 1 = 0 Answer
0.531 is greater than 0.456
Answer:
(3) Driving in a straight line at 100 kilometers per hour
Step-by-step explanation:
let us see each at a time.
(1) Slaming on the brakes causes the speed to become 0units/sec and car comses to rest. the car experiences deceleration (negative acceleration), we can role this one out.
(2) Going from 0 to 100Kilometers per hour, speed increases from 0 to 100km/s in 10 seconds that is acceleration. we can rule this one out.
(3) Driving in a straight line with 100km/hour velocity, here we have constant velocity and there is no acceleration so in this case we are not accelerating.
Answer:
one
Step-by-step explanation:
D. solutions; all numbers on the line